All categories

3 years ago

Which of the following

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

-12 = 3/4n + 8....subtract 8 from both sides

-12 - 8 = 3/4n

-20 = 3/4n.....multiply both sides by 4/3, cancelling the 3/4 on the right

-20 (4/3) = n

-80/3 = n

ur answer is A

You might be interested in

Help plz:))) I’ll mark u brainliest

eimsori [14]

X=-1 give me thanks :)

3 0

2 years ago

WILL GIVE BRAINLESS<br> what is the missing number of 4:9=36:

lora16 [44]

Answer:

Step-by-step explanation:

4 : 9

36 : ?

to get from 4 to 36, you multiply 9

9 x 9 = 81

7 0

2 years ago

Find the taylor polynomial t3(x) for the function f centered at the number

inysia [295]

Answer:

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

Step-by-step explanation:

We are given that

$f(x)=7tan^{-1}(x)$

a=1

$T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}$

Substitute n=3 and a=1

$t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}$

$f(x)=7tan^{-1}(x)$

$f(1)=7tan^{-1}(1)=7\times \frac{\pi}{4}=\frac{7\pi}{4}$

Where $tan^{-1}(1)=\frac{\pi}{4}$

$f'(x)=\frac{7}{1+x^2}$

Using the formula

$\frac{d(tan^{-1}(x))}{dx}=\frac{1}{1+x^2}$

$f'(1)=\frac{7}{2}$

$f''(x)=\frac{-14x}{(1+x^2)^2}$

$f''(1)=-\frac{7}{2}$

$f''(x)=-14x(x^2+1)^{-2}$

$f'''(x)=-14((x^2+1)^{-2}-4x^2(x^2+1)^{-3}})$

By using the formula

$(uv)'=u'v+v'u$

$f'''(x)=-14(\frac{x^2+1-4x^2}{(1+x^2)^3}$

$f'''(x)=(-14)\frac{-3x^2+1}{(1+x^2)^3}$

$f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}$

Substitute the values

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3$

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

7 0

3 years ago

(Number 5)help plzzz

EleoNora [17]

Answer:

See below.

Step-by-step explanation:

So we want to prove that:

$\sqrt8+\sqrt2=3\cdot 2^{\frac{1}{2}}$

First, simplify √8. This is the same as:

$\sqrt8=\sqrt{4\cdot 2}=\sqrt4\cdot\sqrt2=2\sqrt2$

Therefore, our equation is now:

$2\sqrt2+\sqrt2=3\cdot2^{\frac{1}{2}}$

Combine like terms on the left:

$3\sqrt2=3\cdot 2^\frac{1}{2}}$

The square root of something is the same as taking that number to the one-half power. Thus:

$3(2)^\frac{1}{2}}=3\cdot 2^\frac{1}{2}}$

Rewrite:

$3\cdot2^\frac{1}{2}}\stackrel{\checkmark}{=}3\cdot2^\frac{1}{2}}$

And we're done!

6 0

2 years ago

How much degrees turn in the hour hand from 4 to 8

Gala2k [10]

Answer:

120°

I just used a protractor tool lol. I looked it up afterwards as well and 120° is correct.

4 0

3 years ago