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Andrew [12]
2 years ago
5

Find the value that completes the proportion

Mathematics
1 answer:
IrinaK [193]2 years ago
3 0
45 because you multiply the 8 by 9 to get 72 and then you multiply 5 by 9 to get 45
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Help me please ASAP
Oliga [24]

Answer:

30

Step-by-step explanation:

if im reading the qestuion right

so she had 80 bucks she spend 20 on a ticked so she has 60 left so if im reading it right she spent all of her money so 60 divde by 2 is 30.  

hoped this helped!

3 0
2 years ago
Helpppppppppppppppppppppppppppppp
Diano4ka-milaya [45]
In this case it is to find the roots of the polynomial.
 We have then:
 2x ^ 2-5x + 1 = 3
 Rewriting:
 2x ^ 2-5x-2 = 0
 Applying resolver we have
 x = (- b +/- root (b ^ 2 - 4ac)) / (2a)
 Substituting values:
 x = (- (- 5) +/- root ((- 5) ^ 2 - 4 (2) (- 2))) / (2 (2))
 x = (- (- 5) +/- root ((25 + 16)) / (2 (2))
 x = (5 +/- root (41))) / (4)
 x = ((5/4) +/- (root (41)) / 4)
 Answer:
 x = ((5/4) +/- (root (41)) / 4)
 (option 4)
8 0
3 years ago
Can u help me please
tiny-mole [99]

Im pretty sure its D

5 0
3 years ago
Read 2 more answers
One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
What is the maximum number of pages the report can have so that it can be completely stored on a USB drive that holds 4 \cdot 10
lana [24]

Answer:

<em>2,300,000pages  report.</em>

Step-by-step explanation:

Given a USB drive with memory of 4.6*10⁶KB, in order to know the maximum number of pages a report can have so that it can be completely stored on the drive, the conversion factor must be used.

We must first understand that 1 page of a document uses up approximately 2kB of the storage.

Since 2kB = 1page

4.6*10⁶KB = x page

Cross multiply

2kB * x = 4.6*10⁶KB * 1

2x =  4.6*10⁶

x =  4.6*10⁶/2

x =  2.3*10⁶

x = 2,300,000

<em>Hence the maximum number of pages that the report can have so that it can be completely stored on a USB drive that holds 4.6*10⁶KB is approximately 2,300,000pages  report.</em>

4 0
3 years ago
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