A manufacturing company makes 1125 items every hour. which or these statements are true ? Check all that apply

Mathematics

1 answer:

Inessa05 [86]2 years ago

4 0

Answer:

I need to see the statements to answer your question

You might be interested in

The perimeter of a square is 44 centimeters. what is its area?

aalyn [17]

Answer:

Perimeter = 44cm

we know that square has 4 sides which are same

so perimeter means sum of all 4 sides

4 × s = 44cm

s = 11cm

Each side will be of 11cm.

Now area of square is Square of its side length.

so area = 11 × 11 = 121 cm^2

8 0

2 years ago

En una ciudad se registró una temperatura de 12°c bajo cero a las 3:00 am si a las 7:00am del mismo dia la temperatura era tres

hjlf

Answer:

24°c

Step-by-step explanation:

Cuando se dice que la temperatura esta "mayor" significaria que esta aumentando y entorno subiendo a ser mas caliente. Siendo este el caso, si la temperatura a las 3:00 estaba a 12c bajo cero entonces a las 7:00 estaria a 24c. Esto es por que un aumento de tres vecesseria un aumento de 36 grados (12*3). 12c grados bajo cero seria un numero negativo y si sumamos estos numeros nos daria 24c grados.

-12 + 36 = 24

7 0

2 years ago

I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be

Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

$P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}$

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: $g'(-1)\,(1)$ since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: $g'(-1)= 7$ as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1