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defon
3 years ago
13

hi! Hope you're feeling great.. If you're reading this i want you to know that everything will be alright okay? You're gonna go

through everything dont worry. I just wanted you to know that you're doing grate and I'm really proud of you ​
Mathematics
2 answers:
Nutka1998 [239]3 years ago
8 0

Answer:

thx for the metal support. we really need this at this situation

Katen [24]3 years ago
7 0

Answer:

Aww Thanks And To You Too!!! :)

Step-by-step explanation:

Sorry If I put This Late! :)

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What is the answer to −6(x +2) − 2
kkurt [141]

Answer: hii <3

<em>The Answer Is </em>= <u>−6x−14</u>

Step-by-step explanation:

Simplify the expression.

Hopefully this helps <em>you</em>

- Matthew :)

7 0
3 years ago
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PLEASE HELP ME IF I DONT GET THIS RIGHT I FAIL THIS CLASS WILL GIVE CORRECT ANSWER BRAINLIEST PLUS 15 POINTS
Stells [14]
M<CAB= m<C'A'B that is the answer
8 0
3 years ago
Choose the function whose graph is given below.
Natalija [7]

Answer:

option C is correct, i.e. y = sec(x).

Step-by-step explanation:

Given is a graph of a trigonometric function.

We have four choices to select from:-

A. y = cot(x)

B. y = tan(x)

C. y = sec(x)

D. y = csc(x)

We can check the y-intercept from the graph that is (0, 1).

Substituting x=0 in each option as follows:-

A. y = cot(0) = ∞.

B. y = tan(0) = 0.

C. y = sec(0) = 1.

D. y = csc(0) = ∞.

Hence, option C is correct, i.e. y = sec(x).

6 0
4 years ago
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In the equation 2x + 2y = 5 , the slope is -1.<br> True or false?
astra-53 [7]
Convert the equation to the slope-intercept form:

2x+2y=5 \\&#10;2y=-2x+5 \ \ \ |\div 2 \\&#10;y=-x+\frac{5}{2} \\ \\&#10;y=mx+b, \ m - \hbox{the slope} \\&#10;y=-x+\frac{5}{2} \\&#10;\boxed{m=-1} - \hbox{the slope}

TRUE
6 0
3 years ago
X^y=y^x find derivitive
Igoryamba

Answer:

y'=\frac{y^2-xy\ln(y)}{x^2-xy\ln(x)}

Step-by-step explanation:

Take natural log of both sides first.

x^y=y^x

\ln(x^y)=\ln(y^x)

Taking the natural log of both sides allows you to bring down the powers.

y\ln(x)=x\ln(y)

I'm going to differentiate both sides using the power rule.

(y)'(\ln(x))+(\ln(x))'y=(x)'(\ln(y))+(\ln(y))'x

Now recall (ln(x))'=(x)'/x=1/x while (ln(y))'=(y)'/y=y'/y.

y'(\ln(x))+\frac{1}{x}y=1(\ln(y))+\frac{y'}{y}x

Simplifying a bit:

y' \ln(x)+\frac{y}{x}=\ln(y)+\frac{y'}{y}x

Now going to gather my terms with y' on one side while gathering other terms without y' on the opposing side.

Subtracting y'ln(x) and ln(y) on both sides gives:

\frac{y}{x}-\ln(y)=-y'\ln(x)+\frac{y'}{y}x

Now I'm going to factor out the y' on the right hand side:

\frac{y}{x}-\ln(y)=(-\ln(x)+\frac{x}{y})y'

Now we get to get y' by itself by dividing both sides by (-ln(x)+x/y):

\frac{\frac{y}{x}-\ln(y)}{-\ln(x)+\frac{x}{y}}=y'

Now this looks nasty to write mini-fractions inside a bigger fraction.

So we are going to multiply top and bottom by xy giving us:

\frac{y^2-yx\ln(y)}{-xy\ln(x)+x^2}=y'

y'=\frac{y^2-xy\ln(y)}{x^2-xy\ln(x)}

5 0
3 years ago
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