Computer programming 2

In a program, you need to store the identification numbers of 10 employees (as integers) and their weekly gross pay (as double v

dedylja [7]

Answer:

The code to the given question can be given as:

Code:

1)

2 arrays that used to store 10 employee identification number and grosspay amount in parallel and its data-type is int and double.

int Employee_id[10]; //array that store integer value

double Weekly_Gross_Pay[10]; //array that store double value

2)

Define loop for print the details of employees’ identification number and weekly gross pay.

for(int i=0; i<10; i++)

{

cout <<Employee_id[i] <<" " << Weekly_Gross_Pay[i] << endl;

}

Explanation:

The explanation of the above code can be given as:

In Code (1) we declare two array that's data-type is integer and double. In Employee_id array it store the integer values and Weekly_Gross_Pay it store the double value.

In Code(2) It is used to print the value of array. In that code, we used for a loop because of its entry control loop and we know the size of the array. In this loop, we declare a variable (i) and initialized the value 0 and check the condition(i)less than 1 and increment of i. It prints all the 10 values.

5 0

3 years ago

Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the elemen

Verdich [7]

Answer:

Replace <STUDENT CODE> with

for (i = 0; i < SCORES_SIZE; ++i) {

if(lowerScores.at(i)<=0){

lowerScores.at(i) = 0;

}

else{

lowerScores.at(i) = lowerScores.at(i) - 1;

}

Explanation:

To do this, we simply iterate through the vector.

For each item in the vector, we run a check if it is less than 1 (i.e. 0 or negative).

If yes, the vector item is set to 0

If otherwise, 1 is subtracted from that vector item

This line iterates through the vector

for (i = 0; i < SCORES_SIZE; ++i) {

This checks if vector item is less than 1

if(lowerScores.at(i)<1){

If yes, the vector item is set to 0

lowerScores.at(i) = 0;

}

else{

If otherwise, 1 is subtracted from the vector item

lowerScores.at(i) = lowerScores.at(i) - 1;

}

Also, include the following at the beginning of the program:

<em>#include <vector></em>

8 0

3 years ago

How does Google work, why does it work that way?

Oxana [17]

Answer:

Google uses automated programs called spiders or crawlers, just like most search engines, to help generate its search results. Google has a large index of keywords that help determine search results. ... Google uses a trademarked algorithm called PageRank, which assigns each Web page a relevancy score.

8 0

3 years ago

Read 2 more answers

You notice that somehow you have duplicate records for some of your clients in your database. What should you do?

IRINA_888 [86]

Inspect them and make sure that they are exact copies then delete one if they are the same.

5 0

3 years ago

Read 2 more answers

A blood bank maintains two tables - DONOR, with information about people who are willing to donate blood and ACCEPTOR, with info

Kipish [7]

Answer:

The sql query is given below.

Since we need to count of males and females for a particular blood group, we put xxx for the blood group.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors,

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

Explanation:

The clauses in the query are as follows.

1. SELECT: all the columns required in the output are put in this clause.

2. FROM JOIN ON: the table(s) from which the above columns are taken are put in this clause.

3. WHERE: any condition required to filter the output is put in this clause.

The query is explained below.

1. Find the number of male donors. Number of anything can be found using COUNT() function. A query is required since gender is included in deciding the type of donor.

2. The query is defined to find number of male donors as follows.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "M%"; )

3. In the previous query, LIKE operator is used since it is not defined what value is stored for male donors.

4. Similarly, the query to find the number of female donors is formed.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "F%"; )

5. Next, the final query is formed as follows.

SELECT: both COUNT() functions will come here.

FROM: table name

WHERE: specific blood group will be put here

GROUP BY: this clause is optional and is not used in this query.

HAVING: this clause is optional and is not used in this query.

6. The query after putting all clauses is shown below.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%"),

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%")

FROM DONOR

WHERE BG = xxx;

7. Alias is used in the above query for each column to get the final query.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors, COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

7 0

3 years ago