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liubo4ka [24]
2 years ago
8

HELP PLEASE ILL GIVE YOU BRAINLEST IF U GIVE ME THE CORRECT ANSWER FOR THE QUESTION IN THE PIC

Mathematics
1 answer:
anastassius [24]2 years ago
3 0

Answer:

b. <em>f</em>(3.5) = 52

Hope this helps!

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How do you write the difference of a number and eight, divided by ten
ch4aika [34]

Answer:

(x-8)/10

Step-by-step explanation:

-------

7 0
3 years ago
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5x - 5 = 5(x+1) need help
bezimeni [28]

Answer:

There are no solutions.

Step-by-step explanation:

5x-5=5(x+1)

5x-5=5x+5

    +5     +5

5x=5x+10    

-5x -5x

0x=10

There are no possible answers.

Hopefully this helps.

7 0
3 years ago
Simplify (5+1)^2-(12+3^2)/3
lakkis [162]

Answer:

29

Step-by-step explanation:

Simplify the expression (5+1)^2-\dfrac{12+3^2}{3} step by step:

1.

(5+1)^2=6^2=6\cdot 6=36

2.

\dfrac{12+3^2}{3}=\dfrac{12+3\cdot 3}{3}=\dfrac{12+9}{3}=\dfrac{21}{3}=7

Now,

(5+1)^2-\dfrac{12+3^2}{3}=36-7=29

3 0
3 years ago
Read 2 more answers
A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use of one particular cust
Fiesta28 [93]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given set of values

321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320

STEP 2: Write the formula for calculating the Standard deviation of a set of numbers

\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ where\text{ }x_i\text{ are data points,} \\ \bar{x}\text{ is the mean} \\ \text{n is the number of values in the data set} \end{gathered}

STEP 3: Calculate the mean

\begin{gathered} \bar{x}=\frac{\sum ^{}_{}x_i}{n} \\ \bar{x}=\frac{\sum ^{}_{}(321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320)}{20} \\ \bar{x}=\frac{8453}{20}=422.65 \end{gathered}

STEP 4: Calculate the Standard deviation

\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\  \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\  \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}

Hence, the standard deviation of the given set of numbers is approximately 76.68 to 2 decimal places.

STEP 5: Calculate the First and third quartile

\begin{gathered} \text{IQR}=Q_3-Q_1 \\  \\ To\text{ get }Q_1 \\ We\text{ first arrange the data in ascending order} \\ \mathrm{Arrange\: the\: terms\: in\: ascending\: order} \\ 320,\: 321,\: 324,\: 360,\: 361,\: 366,\: 369,\: 372,\: 385,\: 397,\: 403,\: 454,\: 459,\: 475,\: 477,\: 482,\: 498,\: 513,\: 558,\: 559 \\ Q_1=(\frac{n+1}{4})th \\ Q_1=(\frac{20+1}{4})th=\frac{21}{4}th=5.25th\Rightarrow\frac{361+366}{2}=\frac{727}{2}=363.5 \\  \\ To\text{ get }Q_3 \\ Q_3=(\frac{3(n+1)}{4})th=\frac{3\times21}{4}=\frac{63}{4}=15.75th\Rightarrow\frac{477+482}{2}=\frac{959}{2}=479.5 \end{gathered}

STEP 6: Find the Interquartile Range

\begin{gathered} IQR=Q_3-Q_1 \\ \text{IQR}=479.5-363.5 \\ \text{IQR}=116 \end{gathered}

Hence, the interquartile range of the data is 116

3 0
1 year ago
CAN YOU PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELP (24 points)
Radda [10]

Answer:

I'll sing out

Step-by-step explanation:

give me a sec

4 0
3 years ago
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