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3 years ago

Which pair of undefined terms is used to define a Ray?

Mathematics

1 answer:

REY [17]3 years ago

4 0

Answer:

The undefined terms which are used to define a ray is:

Point and a line.

Step-by-step explanation:

The undefined terms in coordinate geometry are:

Line, Points and Plane.

since a line do not have any length, Point has a location but no size.

A line has no width and it extends infinitely and is one dimensional.

and a plane extends infinitely in both the dimensions.

Ray:

A ray is part of a line, has one fixed endpoint, and extends infinitely along the line from the endpoint.

Hence, the undefined terms which are used to define a ray is:

Point and a line.

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What is the solution to the equation

Dafna11 [192]

$\sqrt{4t+5}=3-\sqrt{t+5}\\\\D:4t+5\geq0\ \wedge\ t+5\geq0\ \wedge\ \sqrt{t+5}\leq3\\\\t\geq-\dfrac{5}{4}\ \wedge\ t\geq-5\ \wedge\ t\leq6$

therefore
$D:x\in\left< -\dfrac{5}{4};\ 6\right>$

$\sqrt{4t+5}=3-\sqrt{t+5}\ \ \ |^2\\\\(\sqrt{4t+5})^2=(3-\sqrt{t+5})^2\ \ \ |use:(a-b)^2=a^2-2ab+b^2\\\\4t+5=3^2-2\cdot3\cdot\sqrt{t+5}+(\sqrt{t+5})^2\\\\4t+5=9-6\sqrt{t+5}+t+5\ \ \ \ |-t\\\\3t+5=14-6\sqrt{t+5}\ \ \ \ |-14\\\\3t-9=-6\sqrt{t+5}\ \ \ \ |change\ signs$
$9-3t=6\sqrt{t+5}\ \ \ \ |:3\\\\3-t=2\sqrt{t+5}\ \ \ \ |^2\\\\(3-t)^2=(2\sqrt{t+5})^2\\\\3^2-2\cdot3\cdot t+t^2=4(t+5)\\\\9-6t+t^2=4t+20\ \ \ |-4t-20\\\\t^2-10t-11=0\\\\t^2+t-11t-11=0\\\\t(t+1)-11(t+1)=0\\\\(t+1)(t-11)=0\iff t+1=0\ \vee\ t-11=0\\\\t=-1\in D\ \vee\ t=11\notin D$
Answer: t = -1.

7 0

3 years ago

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Please help asap. What is the missing statement and reason from the proof?

Musya8 [376]

A vertical angles and Angles 1 & 3

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2 years ago

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Between which two consecutive integers does ???147 lie?

BartSMP [9]

If those question marks are supposed to be a radical, then 12 and 13. The square root of 147= 12.12, which puts it between 12 and 13.

3 0

3 years ago

2 5/8 ×3 1/7 What's the answer for this ?

nikdorinn [45]

Answer:

$8 \frac{1}{4}$

Step-by-step explanation:

Let us solve

$2 \frac{5}{8} \times 3 \frac{1}{7} \\ \frac{21}{8} \times \frac{22}{7} \\ \frac{462}{56} \\ \frac{462 \div 2}{56 \div 2} \\ \frac{231}{28} \\ \frac{231 \div 7}{28 \div 7} \\ \frac{33}{4} \\ 8 \frac{1}{4}$

hope this helps you.

Please let me know if you have another questions :-)

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2 years ago

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Question: A canary's beak is, at most, 20mm long. Which algebraic inequality represents this situation?

Paul [167]

Answer:

Option (1).

Step-by-step explanation:

Statement given states that "A canary's beak is, at most 20 mm long."

Word "at most" means "the maximum".

So at most length of the beak means "length of the beak is less than equal to 20 mm".

And the expression representing this statement algebraically will be,

x ≤ 20

Therefore, option (1) will be the correct option.

8 0

3 years ago