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Scorpion4ik [409]
3 years ago
15

2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!

Mathematics
1 answer:
ddd [48]3 years ago
5 0
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
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Write an algebraic expression for each statement:
Andrei [34K]

For the given sentences, the algebraic expressions are:

a) N = 110*c - 300

b) N = 12*b

<h3>How to get the algebraic expressions?</h3>

For the first statement:

A 3-digit number, where the tens digit is c, can be written as:

N = 100*a + 10*c + b

Then the hundreds digit is a, and here we know that is 3 less than the tens digit, then:

a = c - 3

The ones digit is b, here we know that it is 0, then b = 0.

Replacing that in our number we get:

N = 100*(c - 3) + 10*c = 110*c - 300

N = 110*c - 300

That is the algebraic expression.

b) A two-digit number can be written as:

N = b*10 + a

Where b is the tens digit and a is the ones digit.

Here we know that the units digit is twice as bit as the tens digit, then:

a = 2b

Replacing that we get:

N = b*10 + a = b*10 + 2b = 12*b

N = 12*b

That is the algebraic expression.

If you want to learn more about algebraic expressions:

brainly.com/question/4541471

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4 0
2 years ago
HELP Whats the value of X ??
klio [65]
Depending what your solving X for what type of equation because it has different rules
4 0
3 years ago
Olive oil has a density of 0.9 g/mL. What is the mass of 200 mL of olive oil?
lesantik [10]
Known, density= mass/ volume
The volume is given as 200ml
Set up an equation and cross-multiply
You get mass = 180g, answer is B

3 0
3 years ago
Solve each system of equations by graphing y=-1/2x+5 and y=3x-2
777dan777 [17]
Just make the equations equal to each other.  -0.5x+5=3x-2.  Solve for x and find that it is 2, via simple algebra.  Since you know x is 2, sub it in in either equation to find y.  y should be 4.  So the point that fits both equation is (2,4).  This shows that the two graphs of these lines will intersect at this exact point.

If you were to graph these two lines, you ould see that the point of intersection is at (2,4) like we solved for.
3 0
3 years ago
The value of
marusya05 [52]

\large\underline{\sf{Solution-}}

We have to find out the value of the fraction.

<u>Let us assume that:</u>

\sf \longmapsto x =2 +   \dfrac{1}{2 +  \dfrac{1}{2 +  \dfrac{1}{2 + ... \infty} } }

<u>We can also write it as:</u>

\sf \longmapsto x =2 + \dfrac{1}{x}

\sf \longmapsto x =\dfrac{2x + 1}{x}

\sf \longmapsto  {x}^{2}  =2x + 1

\sf \longmapsto {x}^{2}  - 2x - 1 = 0

<u>Comparing </u>the given <u>equation</u> with <u>ax² + bx + c = 0,</u> we get:

\sf \longmapsto\begin{cases} \sf a =1 \\ \sf b =  - 2 \\ \sf c =  - 1 \end{cases}

<u>By quadratic formula:</u>

\sf \longmapsto x =  \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{ {( - 2)}^{2} - 4(1)( - 1)} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{4 + 4} }{2 \times 1}

\sf \longmapsto x =  \dfrac{2 \pm \sqrt{8} }{2}

\sf \longmapsto x =  \dfrac{2 \pm2 \sqrt{2} }{2}

\sf \longmapsto x = 1 \pm\sqrt{2}

\sf \longmapsto x = \begin{cases} \sf 1  + \sqrt{2} \\ \sf 1 -  \sqrt{2}  \end{cases}

<u>But </u><u>"</u><u>x"</u><u> cannot be negative. Therefore:</u>

\sf :\implies x = 1 + \sqrt{2}

So, the value of the fraction is 1 + √2.

4 0
2 years ago
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