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Scorpion4ik [409]
3 years ago
15

2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!

Mathematics
1 answer:
ddd [48]3 years ago
5 0
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

2k^2+4k-9k-18=0

2k(k+2)-9(k+2)=0

(2k-9)(k+2)=0

so k=-2 and 9/2

k=(-2, 4.5)
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3 years ago
Find an equation for the nth term of the arithmetic sequence.
amm1812

Answer:

a_n=-301 +37(n-1)

Step-by-step explanation:

arithmetic sequence formula:  a_n=a +(n-1)d

where a is the first term and d is the common difference

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Rearrange the first equation to make a the subject:

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