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3 years ago

❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️❗️ ANSWER ASAP-POINTS AND BRAINLIEST

Mathematics

1 answer:

denis-greek [22]3 years ago

7 0

Answer:

1 and 3

Step-by-step explanation:

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9x + 8y3 – 7 = 3y3 -3<br> 9x+ 5y = 0

Vikki [24]

Answer:

102 actually just add it up

Step-by-step explanation:

add it up

5 0

3 years ago

2. Given: mZABD = rº and mZACB = yo

Ede4ka [16]

Step-by-step explanation:

the angle ABC = 180 - x, as ABD and ABC are complementary angles on top of the bottom line : all angles around a point on one side of a line are always adding up to 180 degrees.

but because we also know that the sum of all angles in a triangle is 180 degrees too, we can say

180 = ACB + ABC + CAB

180 = y + 180 - x + CAB

0 = y - x + CAB

x = y + CAB

x - y = CAB

therefore, the second answer option is correct.

3 0

2 years ago

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

charle [14.2K]

ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

$(f \circ \: g)(x)= \frac{ - 14x}{ - 14} = x$

8 0

3 years ago

To use distributive property solve equation 2(a+3)=-12

WARRIOR [948]

Answer: a= -18/2

Step-by-step explanation:

2a + 2x3 = -12

2a + 6 = -12

2a + 6 - 6 = -12 - 6 ( subtract 6 from both sides)

2a = -18 (Divide 2 by both sides)

a= -18/2

4 0

3 years ago

Write the explicit formula for the geometric sequence.<br><br> a1 = -5 a2 = 20 a3 = -80

Anni [7]

$a_1 = -5;\ a_2 = 20;\ a_3 = -80 \\\\a_2:a_1=r\ and\ a_3:a_2=r\\\\r=20:(-5)=-4\ check\ r=-80:20=-4\\\\a_n=a_1r^{n-1}\to a_n=-5\cdot(-4)^{n-1}=-5\cdot(-4)^{-1}\cdot(-4)^n\\\\=-5\cdot\left(-\dfrac{1}{4}\right)\cdot(-4)^n=\dfrac{5}{4}\cdot(-4)^n\\\\Answer:\boxed{a_n=-5\cdot(-4)^{n-1}\ other\ a_n=\frac{5}{4}\cdot(-4)^n}$

6 0

3 years ago