Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
g(2) = g(–2) = g(5) is never true for the step function. One " = " symbol per pair of g values, please.
The step function, which you're calling "g(x)," is 0 from -infinity up to but not including 0. It's 1 from x just greater than 0 through infinity.
Thus:
g(2) = 1 because x is greater than 0.
g(-2) = 0 because x is less than 0.
g(5) = 1 because x is greater than 0.
The square of the diagonal (d1) of the end face is
.. (d1)^2 = (3 in)^2 +(5 in)^2 = (9 +25) in^2 = 34 in^2
The square of the longest diagonal (d2) will be given by
.. (d2)^2 = (3x in)^2 +(d1)^2
.. = (9x^2 +34) in^2
So, the longest diagonal is
.. d2 = √(9x^2 +34) in
An example is the number 5i
Answer:
x^2-x+3
Step-by-step explanation:
You factor it out which would then make it
(x-4)(x^2-x+3)/x-4
Then you cancel out the common factor, x-4
which leaves you with x^2-x+3
