<h3>Answer: A) 1</h3>
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Explanation:
Let's label each pair of outcomes as an ordered pair (x,y)
x = first spinner outcome
y = second spinner outcome
We have these 12 different possible combos
(1,3),   (1,4),   (1,5),   (1,6)
(2,3),  (2,4),  (2,5),  (2,6)
(3,3),  (3,4),   (3,5),  (3,6)
Focus on the third column where y = 5 for each (x,y) pair. Of this column only (2,5) has x be an even number. The other results in that column have x be odd.
Basically (1,5) is the only possible outcome if we want the first spinner to lan on an even number, and the second spinner to land on 5.