-13x + 3 is decreasing and has a negative slope.
Is jerome also on stationary bicycle for next 10 minute?? if yes then he burn 125 calories at the average of 5 calorie per minute
2th bounce- 80
5th Bounce- (-)200
9th Bounce- (-)560
Every time the ball bounces it loses 40cm because on the first bounce 160cm-120cm=40cm
And the score goes down by 40 every time and since we go into the negatives the negatives sometimes add on top of each other
Applying the angles of intersecting secants theorem, the measures of the arcs are:
m(KL) = 20°; m(MJ) = 80°.
<h3>What is the Angles Intersecting Secants Theorem?</h3>
When two secants intersect and form an angle outside the circle, the measure of the angle formed is half the positive difference of the measures of the intercepted arcs.
Given the following:
m∠MEJ = 1/2(MJ - KL)
30 = 1/2(MJ - KL)
60 = MJ - KL
KL = MJ - 60
m∠MFJ = 1/2(MJ + KL)
50 = 1/2(MJ + MJ - 60)
100 = 2MJ - 60
2MJ = 100 + 60
2MJ = 160
MJ = 160/2
MJ = 80°
KL = MJ - 60 = 80 - 60
KL = 20°
Thus, applying the angles of intersecting secants theorem, the measures of the arcs are:
m(KL) = 20°; m(MJ) = 80°.
Learn more about angles of intersecting secants theorem on:
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When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
Learn more about algebra:
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