Answer:
The correct answer is - 6.8950.61 gm per mole
Explanation:
Given:
One form of hemoglobin is 0.324% Fe by mass
1 hemoglobin = 4 Fe
Solution:
Molar Mass of iron = 55.85
mass of 4 iron atom = 55.85 * 4 = 223.4 gms
0.324 % correspond to 223.4 gms
100 % correspond to = 223.4 *100/0.324
= 68950.61 gm
MM of haemoglobin = 68950.61 gms = 6.8 E4 gms
Out of the photosynthesis (plants).
Options for the question have not been given. They are as follows:
blood vessel length
blood viscosity
blood vessel diameter
blood colloid osmotic pressure
Answer:
blood colloid osmotic pressure
Explanation:
- Peripheral resistance is the resistance to blood flow by blood vessels.
- It is directly proportional to blood vessel length as more the distance to travel, more will be the resistance.
- It is also directly proportional to blood viscosity as more energy is required to push viscous material.
- It is indirectly proportional to blood vessel diameter. More the diameter of the vessel, easier it is for the blood to pass.
- However, it does not depend on blood colloid osmotic pressure. Colloid osmotic pressure is created by the protein components of blood and they do not have any direct impact on blood flow.
Answer:
A group of individuals of the same species occupying a particular geographic area. Populations may be relatively small and closed, as on an island or in a valley, or they may be more diffuse and without a clear boundary between them and a neighboring population of the same species.
Based on the details provided in Act 1, Scene 2, the best describes Romeo’s personality, He is more concerned with what Benvolio thinks than with his own emotions.
<h3>How does Act 1 describe Romeo?</h3>
A young man of nearly sixteen, Romeo is handsome, intelligent, and sensitive.
Though hasty and immature, his idealism and passion make him an extremely likable character.
He lives in the centre of a violent feud between his family and the Capulets, but he is not at all interested in violence.
Thus, option "3" is correct.
To learn more about Romeo’s click here:
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