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9966 [12]
2 years ago
13

Help, Please! There is a Simicircle with a diameter of 36mm, what is the area? Use 3.14 for pi

Mathematics
1 answer:
kondaur [170]2 years ago
4 0

Answer:

28.258mm

Step-by-step explanation:

A semi circle is half of a circle, so we will divide it by 2 after finding the area.

Formula for finding semi circle = pi x radius ÷ 2

Formula for radius = diameter ÷ 2

Radius = 36 ÷ 2 = 18mm

Semi circle = 3.14 or 22/7 x 18 = 56.57

56.57 ÷ 2 = 28.285

Note: I don't have a calculator with me right now, so you might want to consider typing out pi x 18 ÷ 2 on a calculator since my answer might be wrong because the answer has endless decimals.

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Micheal has a sink that is shaped like a half-sphere. The sink has a volume of 3000/3π in^3. One day, his sink is clogged. He ha
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3 0
3 years ago
PLEASE HELP.
Harrizon [31]

ANSWER

The maximum y-value is 0.

EXPLANATION

The domain of the given absolute value function is (-∞, ∞) .

This means the function is defined for all real values of x.

The range of the function is (-∞, 0].

This can be rewritten as

y \leqslant 0

This means that, the highest y-value on the gray of this absolute value function is 0.

Hence the maximum y-value of the function is 0.

3 0
3 years ago
21x+28=14 and 9x+12y=6
Westkost [7]
<span>21x+28=14
x= -2/3 or -0.666666666

</span><span>9x+12y=6
x=2/3 or .666666666
y=0</span>
7 0
3 years ago
We have two fair three-sided dice, indexed by i = 1, 2. Each die has sides labeled 1, 2, and 3. We roll the two dice independent
Bogdan [553]

Answer:

(a) P(X = 0) = 1/3

(b) P(X = 1) = 2/9

(c) P(X = −2) = 1/9

(d) P(X = 3) = 0

(a) P(Y = 0) = 0

(b) P(Y = 1) = 1/3

(c) P(Y = 2) = 1/3

Step-by-step explanation:

Given:

- Two 3-sided fair die.

- Random Variable X_1 denotes the number you get for rolling 1st die.

- Random Variable X_2 denotes the number you get for rolling 2nd die.

- Random Variable X = X_2 - X_1.

Solution:

- First we will develop a probability distribution of X such that it is defined by the difference of second and first roll of die.

- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }

- The corresponding probabilities for each outcome are:

                  ( X = -2 ):  { X_2 = 1 , X_1 = 3 }

                  P ( X = -2 ):  P ( X_2 = 1 ) * P ( X_1 = 3 )

                                 :  ( 1 / 3 ) * ( 1 / 3 )

                                 : ( 1 / 9 )

   

                  ( X = -1 ):  { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }

                 P ( X = -1 ):  P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)

                                 :  ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

                                 : ( 2 / 9 )

         

       ( X = 0 ):  { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } +  { X_2 = 3 , X_1 = 3 }

       P ( X = -1 ):P ( X_2 = 1 )*P ( X_1 = 1 )+P( X_2 = 2 )*P ( X_1 = 2)+P( X_2 = 3 )*P ( X_1 = 3)

                                 :  ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

                                 : ( 3 / 9 ) = ( 1 / 3 )

       

                    ( X = 1 ):  { X_2 = 2 , X_1 = 1 } + { X_2 = 3 , X_1 = 2 }

                 P ( X = 1 ):  P ( X_2 = 2 ) * P ( X_1 = 1 ) + P ( X_2 = 3 ) * P ( X_1 = 2)

                                 :  ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )

                                 : ( 2 / 9 )

                    ( X = 2 ):  { X_2 = 1 , X_1 = 3 }

                  P ( X = 2 ):  P ( X_2 = 3 ) * P ( X_1 = 1 )

                                    :  ( 1 / 3 ) * ( 1 / 3 )

                                    : ( 1 / 9 )                  

- The distribution Y = X_2,

                          P(Y=0) = 0

                          P(Y=1) =  1/3

                          P(Y=2) = 1/ 3

- The probability for each number of 3 sided die is same = 1 / 3.

7 0
3 years ago
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