Answer:
6.66 yards of ribbon.
Step-by-step explanation:
If she has 10 yards of ribbon and divides it equally into three parts, those 3 parts would each be 3.33 yards long or 3 (1/3) yards long.
If she uses two of those parts on gifts, then she would use 3.33 x 2 or 6.66 yards of ribbon.
A) y= x+1
b) y= -2/3x-5
c) y=-1/2x+12
d) y= 4x-3/2
According to my calculations all the answers should be correct.
Answer:
answer given in step by step...
Step-by-step explanation:
13x+13(x+1)+13(x+2)=312
13x+13x+13+13x+26=312
39x+39=312
39x=312-39
39x=273
x=7
first number=13x=13*7=91
second number=13(8)=104
third number=13(9)=117
X = approximately 633
Steps:
lnx + ln3x = 14
ln3x^2 = 14 : Use the log property of addition which is to multiply same log together so you multiply x and 3x because they have log in common
(ln3x^2) = (14) : take base of e on both sides to get rid of the log
e e
3x^2 = e^14 : e cancels out log on the left side and the right side is e^14
x^2 = e^14 / 3 : divide both sides by 3
√x^2 = <span>√(e^14 / 3) : take square root on both sides to get rid of the square 2 on x
</span>
x = √(e^14) / <span>√3 : square root cancels out square 2 leaving x by itself
x = e^7 / </span>√3 : simplify the √(e^14) so 14 (e^14) divide by 2 (square root) = 7<span>
x = </span>633.141449221 : solve
Answer:
10.59%
Step-by-step explanation:
percentage of change is given by
{(old number - new number)/old number} * 100
_________________________
given
no. of student went to the first school dance = 340
no. of student went to the last school dance = 306
Percentage of change between two dance
= ((no. of student went to the first school dance - no. of student went to the last school dance)/ no. of student went to the fist school dance)*100
= (340 - 306)/340 *100
= (36/340 )*100 = 10.59%
The percent of change between the two dances 10.59%.
