A) Isolate y in both inequalities
1) x + y ≥ 4 => y ≥ 4 - x
2) y < 2x - 3
B) Draw the lines for the following equalities:
1) y = 4 - x
2) y = 2x - 3
C) Shade the regions of solutions
1) The region that is over the line y = 4 - x
2) The region that is below the line y = 2x - 3
The solution is the intersection of both regions; this is the sector between both lines that is to the right of the intersection point, including the portion of the very line y = 4 - x and excluding the portion of the very line y = 2x - 3
Answer:
<h2>

</h2>
Solution,
Let the points be A and B
A(-4 , 1)------>( X1, y1)
B(2,4)---------->( x2, y2)
Now,
Gradient:





Hope this helps...
Good luck on your assignment...
Answer:
It will take <u><em>80 days</em></u> for the bull calf to reach a weight of 500 kilograms.
Step-by-step explanation:
Given:
The weight of a bull calf is 388 kilograms.
Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.
Required weight which to be increased = 500 - 388 = 112 kilograms.
Rate of weight increase = 
=
Thus, the time required = 
=
=
<em>The time required = 80 days</em>.
Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.
(x-3)^2, as x-3 is repeated twice
The emf of a cell is mathematically given as
= 0.0532 v
<h3>What is the emf of a cell?</h3>
Generally, the equation for emf is mathematically given as

where,
Pb is lead
H is hydrogen
/ Pb has a standard reduction potential of -0.126 volts, while
/
has a standard reduction potential of 0.0 volts.

![[Pb^2^+] x [H^+]^2](https://tex.z-dn.net/?f=%5BPb%5E2%5E%2B%5D%20x%20%5BH%5E%2B%5D%5E2)
= 0.126 - 0.059/2 log 1 / [0.57] x [0.09]^2
= 0.0532 v
Read more about emf
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