Answer:

Step-by-step explanation:
From figure,

In triangle 

![\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]](https://tex.z-dn.net/?f=%5CRightarrow%20%28a%2Bb%29%5E2%3D%28a-b%29%5E2%2B%28O%27%20D%29%5E2%5C%5C%5CRightarrow%20a%5E2%2Bb%5E2%2B2ab-a%5E2-b%5E2%2B2ab%3D%28O%27%20D%29%5E2%5C%5C%5CRightarrow%204ab%3D%28O%27%20D%29%5E2%5C%5C%5CRightarrow%20O%27D%3D2%5Csqrt%7Bab%7D%20%5C%5C%5CRightarrow%20O%27%20D%3D2%5Csqrt%7Bab%7D%3DAB%20%5Cquad%20%5Cquad%20%5B%5Cbecause%20O%27%20DAB%5C%3B%5C%3B%20%5Ctext%7Bis%20a%20rectangle.%7D%5D)
Hence, 
Answer:
i think it might be 118.4
Step-by-step explanation:
Check the picture below.
that means
angle AFB is 27 + 2 = 29
angle BFC is 2(27) + 12 = 66
and angle CFD is 2(27) or 54
so hmmmm, you'd know which one isn't there.
Cot 8° 13'=cot(8+13/60)
=cot(8+.216......)
=cot8.216......
=cos/sin8.216......
=6.925...........
Answer:
Quadrant IV
Step-by-step explanation:
Given

Required
The quadrant of the terminal side
To do this, we simply rotate the given angle in a clockwise direction.
A complete rotation is 
So, we have:


Remove the complete rotation

<em>When </em>
<em> is rotated in the clockwise direction, it stops at the 4th quadrant.</em>
<em>Hence, the terminal side falls in the quadrant IV</em>
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