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ella [17]
3 years ago
13

If one leg of a right triangle is 6 units and the other leg is 8 units, what is the length of the hypotenuse. {in units}

Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

c=10 units

Step-by-step explanation:

The Pythagorean Theorem states that a^2+b^2=c^2.

This means that the sides are represented by a^2+b^2. In order to find the hypotenuse in this problem, we substitute a and b for 6 and 8.

6^2+8^2=c^2

we do what it shows us and get:

36+64=c^2

from there, we add the left side altogether then square each side to get rid of the root.

100=c^2

√100=√c^2

and we get c =<em> 10 units.</em>

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Answer:

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kap26 [50]
Cosine (x) = 4 over 5
cos
(
x
)
=
4
5
Explanation:
First you must apply sohcahtoa
it means
sine = opposite side over hypotenuse
sine = opposite/hypotenuse
cosine = adjacent side over hypotenuse
cosine = adjacent/hypotenuse
tangent = opposite side over adjacent side
tangent = opposite/adjacent
then
solve the unknown by applying the Right Triangle Theorem.
draw a right triangle.
label the parts where
a
is the opposite side
b
is the adjacent side
c is the hypotenuse
Solve the unknown. The hypotenuse using
a
2
+
b
2
=
c
2

since the given
tan
x
=
3
4

it means
tan = opposite/adjacent
a
= opposite side =
3

b
= adjacent side =
4

c
= hypotenuse = ??
a
2
+
b
2
=
c
2

substitute the value
(
3
)
2
+
(
4
)
2
=
c
2

9
+
16
=
c
2

25
=
c
2

get the square root of
25

it is equal to
5

therefore
c
=
5

c
= hypotenuse =
5

cos
= adjacent/hypotenuse
cos
(
x
)
=
4
over
5

cos
(
x
)
=
4
5
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