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oksian1 [2.3K]
3 years ago
11

A box contains 5 red marbles, 6 white marbles, and 4 blue marbles. find p(red or blue)

Mathematics
2 answers:
vladimir1956 [14]3 years ago
5 0
That is what i think is the right answer.

9/15=3/5
Stells [14]3 years ago
3 0

for the red it is 5out of 15 or 3/5

and for the blue it is 4/15

and if it wants it together it is 9/15 or 3/5

hope this helps

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A textbook store sold a combined total of 290 math and history textbooks in a week. The number of math textbooks sold was 64 mor
11Alexandr11 [23.1K]

Answer:

113

Step-by-step explanation:

290 - 64 = 226

226 ÷ 2 = 113

4 0
2 years ago
A bag of marbles contains 5 red, 3 blue, 2 green, and 2 yellow marbles. What is the probability that you choose a blue marble an
ira [324]

PART ANSWER:

Hi. I don't know the entire answer but I do know the probability of chosing a blue marble once is 25%.

5 + 3 + 2 + 2 = 12

3/12 or 1/4 = 25% or .25

Sorry I could not fully help.

6 0
3 years ago
Read 2 more answers
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
Simplify the ratio 0.08:0.12
mr Goodwill [35]

0.08:0.12\\\\0.08\cdot100=8\\0.12\cdot100=12\\\\0.08:0.12\to8:12\\\\8:4=2\\12:4=3\\\\0.08:0.12\to8:12\to2:3

4 0
3 years ago
Read 2 more answers
Simplify completely quantity 6 x minus 12 over 10.
Natali [406]
Hey! 
So we have 6 multiplied by -12 and that is over 10
so we are multiplying a positive number by a negative number. When you do that the answer will be a negative number. 
Now we have -72/10
we can simplify that more
divide the numerator and denominator by 2 because that is the largest number that is divisible by both number
now it is -36/5
The answer is -36/5
Hope this helps!
8 0
3 years ago
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