Answer:
b. these codes are equal volume
From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)
Hence, we can say that it's:
![\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5E%7Bc%7Dy%5E%7B5%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%283x%5E%7B2%7Dy%29%5E%7B3%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B6y%5E%7Bd%7D%7D)
![= \sqrt[3]{162x^{6}y^{3+d}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B162x%5E%7B6%7Dy%5E%7B3%2Bd%7D%7D)
Hence, c = 6 and d = 2
To add fractions, first convert them to have equal denominators.
3/4= 9/12 (multiply both sides by 3)
2/3= 8/12 (multiply both sides by 4)
From here, add the numerators while keeping the denominator.
9/12+ 8/12= 17/12
Final answer: 17/12 or 1 5/12
Answer:
the answer is 2.620
Step-by-step explanation:
the way u will get this is at the top there pattern is adding the bottom they are subtracting 2
<u>G</u><u>iven </u><u>:</u><u>-</u>
- A right angled triangle with two sides 10cm and 9cm .
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Solution</u><u> </u><u>:</u><u>-</u>
At angle theta , 9cm side will be considered as the perpendicular and 10cm side will be hypotenuse . So , as we know that ;
Substituting the respective values,
Simplify,
Take arcsin both sides ,
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>6</u><u>4</u><u>.</u><u>1</u><u>5</u><u>°</u><u> </u><u>.</u><u> </u>