Please solve this problem 7 + x8

Effectus [21]

Answer:

17cm

Step-by-step explanation:

Given that the Volume of a cone is 4,000 cm³. And we need to determine the height of the cone , if the diameter is 30cm .

Diagram :-

$\setlength{\unitlength}{1.2mm}\begin{picture}(5,5)\thicklines\put(0,0){\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\put(-0.5,-1){\line(1,2){13}}\put(25.5,-1){\line(-1,2){13}}\multiput(12.5,-1)(2,0){7}{\line(1,0){1}}\multiput(12.5,-1)(0,4){7}{\line(0,1){2}}\put(17.5,1.6){\sf{15cm }}\put(9.5,10){\sf{17\ cm }}\end{picture}$

Step 1: Using the formula of cone :-

The volume of cone is ,

$\rm\implies Volume_{(cone)}=\dfrac{1}{3}\pi r^2h$

Step 2: Substitute the respective value :-

$\rm\implies 4000cm^3 =\dfrac{1}{3}(3.14) ( h ) \bigg(\dfrac{30cm}{2}\bigg)^2$

As Radius is half of diameter , therefore here r = 30cm/2 = 15cm .

Step 3: Simplify the RHS :-

$\rm\implies 4000 cm^3 = \dfrac{1}{3}(3.14) ( h ) (15cm)^2\\$

$\rm\implies 4000 cm^3 = \dfrac{1}{3}(3.14) ( h ) 225cm^2\\$

Step 4: Move all the constant nos. to one side

$\rm\implies h =\dfrac{ 4000 \times 3}{ (3.14 )(225 )} cm \\$

$\implies \boxed{\blue{\rm Height_{(cone)}= 16.98 \approx 17 cm }}$

Hence the height of the cone is 17cm .

5 0

3 years ago

G(x) =x^4+x^3+4x^2+4x

weeeeeb [17]

Answer:

$g(x) = x {}^{4} + x {}^{3} + 4x {}^{2} + 4x \\ 0 =x {}^{4} + x {}^{3} + 4x {}^{2} + 4x \\ x {}^{4} + x {}^{3} + 4x {}^{2} + 4x = 0 \\ x {}^{3} \times (x + 1) + 4x \times (x + 1) = 0 \\ x \times (x + 1) \times (x {}^{2} + 4) = 0 \\ x = 0 \\ x + 1 = 0 \\ x { }^{2} + 4 = 0 \\ \\ x \frac{}{1} = - 1 \\ x \frac{}{2} = 0$