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2 years ago

Someone help? I need to get this right!

Mathematics

2 answers:

Lelechka [254]2 years ago

8 0

Answer:

I think the answer is b

Step-by-step explanation:

ludmilkaskok [199]2 years ago

3 0

Answer:

I pretty sure the answer is B

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ra1l [238]

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3 years ago

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dezoksy [38]

The correct answer is C!!

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3 years ago

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likoan [24]

Answer:

$\frac{4\sqrt{5} }{5}$

Step-by-step explanation:

$\frac{4\sqrt{6} }{\sqrt{30} } =\frac{\sqrt{30} *4*\sqrt{6} } \sqrt{30} {\sqrt{30} } \\\\$

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2 years ago

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2 years ago

Determine the points of intersection of the equation circumference x² + (y-3) ² = 25 with the coordinate axes.

KengaRu [80]

Answer:

$x^2 +(y-3)^2 = 25$

And we want to find the coordinate axes so then we can do the following:

If x=0 we have:

$0^2 +(y-3)^2 = 25$

$(y-3)^2= 25$

$y-3= \pm 5$

$y_1 = 5+3=8$

$y_2 = -5+3=-2$

Now of y =0 we have:

$x^2 +9 = 25$

$x^2 = 16$

$x= \pm 4$

And then the coordinate axes are:

(4,0) (-4,0), (0,8), (0,-2)

Step-by-step explanation:

For this cae we have the following functon given:

$x^2 +(y-3)^2 = 25$

And we want to find the coordinate axes so then we can do the following:

If x=0 we have:

$0^2 +(y-3)^2 = 25$

$(y-3)^2= 25$

$y-3= \pm 5$

$y_1 = 5+3=8$

$y_2 = -5+3=-2$

Now of y =0 we have:

$x^2 +9 = 25$

$x^2 = 16$

$x= \pm 4$

And then the coordinate axes are:

(4,0) (-4,0), (0,8), (0,-2)

7 0

2 years ago