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3 years ago

ANSWER THE QUESTIONS BELOW ABOUT BIOLOGY!! WILL GIVE BRAIN!!

Biology

1 answer:

Murrr4er [49]3 years ago

4 0

Explanation:

This was a bit annoying to do, but as I said, I'm just happy to help, incomplete dominance will blend the traits together (Ex: White + Red = pink) (Ex. Blue + Red = Purple)

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Svetlanka [38]

5) muscles work in pairs to move bones

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3 years ago

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bogdanovich [222]

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3 years ago

In pea plants , yellow pod color is recessive and green pod color is dominant . A heterozygous dominant for that trait . What pe

almond37 [142]

The question is incomplete. The complete question is:

In pea plants, yellow pod color is recessive and green pod color is dominant. A heterozygous plant produced offspring with a plant that is homozygous dominant for the trait. What is a percent chance that the pea plant will have green pods.

Answer:

100%

Explanation:

Let's assume that the allele "G" gives green pod color while the allele "g" imparts yellow color to the pods. The genotype of the heterozygous plant would be "Gg". A cross between heterozygous green plant (Gg) with homozygous dominant (GG) plant would produce progeny in following ratio=

Gg x GG= 1/2 GG (green): 1/2 Gg (green)

Therefore, there are 100% chances that the progeny plant will have green pods.

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4 years ago

Read 2 more answers

A concentration gradient affects the direction that solutes diffusion. Describe how molecules move with respect to the concentra

Shtirlitz [24]

Answer:a

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3 years ago

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Assume that the genes for tan body and bare wings are 15 map units apart on chromosome II in Drosophila. If a tan-bodied, bare-w

Fittoniya [83]

Answer:

WILD TYPE= 425;

TAN-BARE= 425;

TAN= 75;

BARE= 75

Explanation:

Fifteen map units apart implies that 15% of the offspring are products of recombination.

Out of 1000 offsprings, therefore 15% of 1000= 0.15 × 1000=150

150 offsprings are products of recombination.

100-15 =85%

Therefore, 85% of the offspring are parental.

So, if tan-bodied, ware-winged female was mated with wild-type male resulting in F1 phenotypically wild-type females were mated to tan-bodied, bare-winged males.

The expected number of offsprings that are tanned but have normal wings would be:

Wild type= 50% of 850

0.50 × 850 = 425

Tan-bare= 50% of 850

0.50 × 850 = 425

tan= 50% of 150

0.50×150= 75

Bare= 50% of 150

0.50×150=75

7 0

4 years ago