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Phantasy [73]
3 years ago
8

ILL MARK YOU BRAINLIEST

Mathematics
2 answers:
swat323 years ago
8 0

Answer:

I believe its 8

Step-by-step explanation:

notka56 [123]3 years ago
5 0

Answer:

(Q1) = 5

Step-by-step explanation:

First, you have to find the median which is 10.

The drawing will demonstrate everything you need to know.

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They give me this in 7th grade
insens350 [35]

Answer:

3x - 8 = 2x + 12

(vertical angles)

x = 20

A straight line = 180 degrees,

so 3(20)-8=52

52+128 = 180

so y is 128.

8 0
3 years ago
A rectangular box has three of its faces on the coordinate planes and one vertex in the first octant on the paraboloid z=100−x2−
LuckyWell [14K]

The volume as a function of the location of that vertex is

... v(x, y, z) = x·y·z = x·y·(100-x²-y²)


This function is symmetrical in x and y, so will be a maximum when x=y. That is, you wish to maximize the function

... v(x) = x²(100 -2x²) = 2x²(50-x²)


This is a quadratic in x² that has zeros at x²=0 and x²=50. It will have a maximum halfway between those zeros, at x²=25. That maximum volume is

... v(5) = 2·25·(50-25) = 1250


The maximum volume of the box is 1250 cubic units.

7 0
3 years ago
A farmer fills a rectangular water trough to a depth of 1 foot.
Jet001 [13]

Answer:

Step-by-step explanation:

Is 8ft

8 0
3 years ago
Read 2 more answers
The population of a certain species of insect is given by a differentiable function P, where P(t) is the number of insects in th
Step2247 [10]

Answer:

\frac{dP}{dt} \ =\  \frac{1}{5}P

Step-by-step explanation:

Given

Variation: Directly Proportional

Insects = 10 million when Rate = 2 million

i.e. P = 10\ million when \frac{dP}{dt} = 2\ million

Required

Determine the differential equation for the scenario

The variation can be represented as:

\frac{dP}{dt} \ \alpha\ P

Which means that the rate at which the insects increase with time is directly proportional to the number of insects

Convert to equation

\frac{dP}{dt} \ =\ k * P

\frac{dP}{dt} \ =\ kP

Substitute values for \frac{dP}{dt} and P

2\ million = k * 10\ million

Make k the subject

k = \frac{2\ million}{10\ million}

k = \frac{2}{10}

k = \frac{1}{5}

Substitute \frac{1}{5} for k in \frac{dP}{dt} \ =\ k * P

\frac{dP}{dt} \ =\  \frac{1}{5}* P

\frac{dP}{dt} \ =\  \frac{1}{5}P

8 0
3 years ago
Simplify: –4(2x – 3y) + 4x – 2(x + 6)
kodGreya [7K]

Multiply the first bracket by -4. Multiply the second bracket by -2

-8x+12y+4x-2x-12

Negative and Negative = Positive

Negative and Positive = Negative

Then do -8x+4x-2x

= -6x+12y-12

Answer is D. -6x+12y-12

4 0
3 years ago
Read 2 more answers
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