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77julia77 [94]
3 years ago
13

Hich is an equation of a circle with center (-5, -7) that passes through the point (0, 0)?

Mathematics
1 answer:
Rzqust [24]3 years ago
3 0
(a;\ b)-the\ coordinates\ of\ center\\r-the\ radius\\\\The\ equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\The\ radius\ is\ equal\ the\ distance\ between\ points\ (-5;-7)\ and\ (0;\ 0)\\\\The\ distance\ between\ A(x_A;\ y_A)\ and\ B(x_B;\ y_B):\\d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}\\\\subtitute:\\r=\sqrt{(0-(-5))^2+(0-(-7))^2}=\sqrt{5^2+7^2}=\sqrt{25+49}=\sqrt{74}\\\\\boxed{(x-(-5))^2+(y-(-7))^2=(\sqrt{74})^2\to(x+5)^2+(y+7)^2=74}
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Yeah but, now I'm dodging potholes in my sunburnt Silverado

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I said "Girl, you've never seen stars like the ones back home"

And she said "Maybe I should, see 'em for myself"

[Chorus]

Yeah, but now I'm dodging potholes in my sunburnt Silverado

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Oh, but now I'm dodging potholes in my sunburnt Silverado

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Somethin' 'bout the way she kissed me tells me she'd love Eastern Tennessee

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Yeah, but all I brought back with me was some sand in my boots

Step-by-step explanation:

7 0
2 years ago
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8 0
3 years ago
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Answer:

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Step-by-step explanation:

For this example, we can just use a calculator and find out that both (3^5)^4 and (3^4)^5 are the same value. But how do we know this algebraically?

When dealing with exponents, we must have a good understanding of the properties of exponents before doing any calculations.

For this example, I recognize that the power rule of exponents is being used:

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So let's apply this rule to the given equation.

(3^5)^4 = (3^4)^5

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Now we know both sides of the equation equal 3^20 (or 3486784401).

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