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3 years ago

Find the unit rate??

Mathematics

2 answers:

grin007 [14]3 years ago

6 0

Answer:

120

Step-by-step explanation:

This method works for any unit rate problem.

I am using the first rate for simplicity.

A unit rate always has a 1 for the numerator.

Convert 2/240 so that it had a 1 for the numerator instead of a 2.

2 divided by 2 is 1.

240 divided by 2 is 120.

120 is your answer.

Why divide 240 by 2?

To get 2 to 1, you need to divide the 2 by 2.

Anything you do to the numerator, (2) you need to do to the denominator (240).

Marrrta [24]3 years ago

4 0

Answer:

wasdwa

Step-by-step explanation:

sdwasdwasd

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Find the compound interest on 800 at 5% per annum for 2 years.

Ludmilka [50]

Answer:

$C = 82$

Step-by-step explanation:

Given

$R = 5\%$ -- Rate

$P = 800$ -- Principal

$N = 2$ -- Time

Required

Determine the compound interest

First, we calculate the Amount (A)

$A = P(1 + R)^N$

$A = 800*(1 + 5\%)^2$

Express % as decimal

$A = 800*(1 + 0.05)^2$

$A = 800*(1.05)^2$

$A = 882$

The compound interest (C) is then calculated as:

$C = A -P$ i.e. Amount - Principal

$C = 882 - 800$

$C = 82$

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2 years ago

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Eva8 [605]

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2 years ago

Read 2 more answers

Solve 5x^2 - 7x + 2 = 0 by completing the square.

Reika [66]

Answer: The correct option is (c) $\dfrac{49}{100}.$

Step-by-step explanation: We are given to solve the following quadratic equation by the method of completing the square:

$5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)$

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

$5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.$

So,

$x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.$