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ANTONII [103]
3 years ago
11

An athletic field has the shape of a 40-yard-by-100-yard rectangle with a semicircle at each end. A running track that is 10 yar

ds wide surrounds the field. Find the area of the track, the shaded portion of the picture. Use 3.14 for pi.
Mathematics
2 answers:
astraxan [27]3 years ago
8 0

Answer:

5000 is the answer

Step-by-step explanation:

mark me brainliest

topjm [15]3 years ago
7 0

Answer:

5000

Step-by-step explanation

100*40= 4000

100*10=1000

4000+1000=5000

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Answer:

Step-by-step explanation:

The co-ordinates of the rectangle are:

A (8, 6)

B (-4, -10)

C (-8, -7)

D (4, 9)

The Area of Rectangle is Given by: <em>length x breadth </em>= AB x BC

Lengths of AB and BC can be found by distance formula

<em>length</em>(AB) = \sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} )^{2}} = \sqrt{(-4-8)^{2} + (-10-6)^{2}} = 20

Similarly,

<em>length</em>(BC) = 5

Area of Rectangle = AB x BC = 20 x 5 = 100 square units

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3 years ago
Strawberries are $3.99 per pound. If a customer bought $30 worth, how many pounds did he buy? $
lubasha [3.4K]

Answer:

7.5

Step-by-step explanation:

Divide 30 by 3.99

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Step-by-step explanation:


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The vertex if the parabola below is at the point (2,4) and the point (3,6) is on the parabola. What is the equations the parabol
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Lynn is trying to determine how far away Student B is from the balloon. He decides to use the
kaheart [24]

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete as the image that illustrates the scenario is not given.</em>

<em>However, I can deduce that the question is about a right-angled triangle.</em>

<em>So, I will give a general explanation on how to find each of the side of the triangle, given a side and an angle.</em>

<em />

<u>For triangle A (solve for b)</u>

Using cosine formula.

\cos \theta = \frac{Adjacent}{Hypotenuse}

\cos 60= \frac{5}{b}

Make b the subject

b= \frac{5}{\cos 60}

<u>For triangle B (solve for b)</u>

Using cosine formula.

\sin \theta = \frac{Opposite}{Hypotenuse}

\sin 60= \frac{b}{5}

Make b the subject

b = 5\sin 60

<u>For triangle C (solve for b)</u>

Using cosine formula.

\tan \theta = \frac{Opposite}{Adjacent}

\tan 60= \frac{b}{5}

Make b the subject

b = 5\tan 60

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2 years ago
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