You can't prove that generalization is likely correct. <em />It is told that generalization is never correct and some has told that generalization is sometimes correct, so I guess that would depend on your thoughts, opinions.
hope this helped!!
~Melany~ ;)

5 0

4 years ago

URGENT PLEASE HELP!! <br><br> Thank you so much !

djverab [1.8K]

Answer:

1. d 2. A 3. c

3 0

3 years ago

Calculate had a net income of 8 million dollars in 2010, while a small competing company, Computate, had a net income of 3 milli

Lilit [14]

The question is an illustration of a linear function and an exponential function.

The given parameters are:

<u>Calculate Company</u>

Initial net income: $8 million

Rate: $0.5 million per year

<u>Computate Company</u>

Initial net income: $3 million

Rate: 20% each year

<h3>(a) Standard mathematical model</h3>

The model of calculate company is best represented using a linear function, while the computate is best modeled by an exponential function.

A linear function is represented as:

$y = mx + b$

Where:

m represents rate
b represents the initial value

An exponential function is represented as:

$y = a(1 + r)^x$

Where:

r represents rate
a represents the initial value

So, the functions are:

$y=8 + 0.5x$ --- calculate company

$y =3(1.2)^x$ --- computate company

See attachment for the graph of both functions

<h3>(b) Compare both functions</h3>

From the graph of both functions, we have the following comparison:

The calculate company has a higher y-intercept
The computate company follows a more realistic model

<h3>(c) The company to choose</h3>

In (b), we concluded that:

The computate company follows a more realistic model

Hence, it is better to invest in the computate company

<h3>(d) When both companies have the same net income</h3>

From the attached graph, both functions meet at approximately (8, 12)

This means that they have the same net income in 2018

The graphs do not meet again.

This means that, they would never have the same net income again