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3 years ago

What are the special purpose books?

Mathematics

2 answers:

horsena [70]3 years ago

8 0

They give you knowledge somehow

Elenna [48]3 years ago

4 0

Answer:

hi Plz Subscribe Sameer Duos Channel

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Find the slope of the line passing through the given points (7, 13) and (2, -12).

tatyana61 [14]

Answer:

The answer is C.

Step-by-step explanation:

m=y²-y¹/x²-x¹

m=(-12)-13/2-7

m=-25/-5

m=5

4 0

3 years ago

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

4 years ago

Read 2 more answers

Can somebody help me with this please

dmitriy555 [2]

Uhhh, kind of an estimated guess but I got $7426.30

4 0

4 years ago

Simplify the following expression<br> (4.1 × 105) + (5.5 × 106)

kakasveta [241]

Answer:

It is 1130.1 hope this helps

5 0

3 years ago

110 as a product of prime numbers

sweet [91]

$110 = 11 \times 10$

$110 = 11 \times \ 5 \times 2$

So it is the product of $5 \times 2 \times 11$

And 2,5 and 11 are prime numbers, so there you go :)

8 0

3 years ago

What are the special purpose books?​

What are the special purpose books?