The solution of the equation –3x + 1 + 10x = x + 4 will be 1/2. Then the correct option is A.
<h3>What is simplification?</h3>
Making anything easier to accomplish or comprehend, as well as making it less difficult, is the definition of simplification.
The equation is given below.
–3x + 1 + 10x = x + 4
On changing, we have
6x = 3
x = 1/2
Then the correct option is A.
More about the simplification link is given below.
brainly.com/question/12616840
#SPJ1
Answer:
b
Step-by-step explanation:
x=2
Perimeter is the total sum of the 4 sides.
The height is given as 8 inches. If this is doubled the new height becomes 16 inches. (The height increases by 8 inches)
total increase in perimeter = 8 + 8 = 16 inches.
Answer: 16 inches
Answer:
P(success at first attempt) = 0.1353
Step-by-step explanation:
This question follows poisson distribution. Thus, the formula is;
P(k) = (e^(-G) × (G)k)/k!
where;
G is number of frames generated in one frame transmission time(or frame slot time)
Let's find G.
To do this, we need to find number of frames generated in 1 slot time which is given as 50 ms.
Now, in 1000 ms, the number of frames generated = 50
Thus; number of frames generated in 50 ms is;
G = (50/1000) × 50
G = 2.5
To find the chance of success on the first attempt will be given by;
P(success at first attempt) = P(0) = e^(-G) = e^(-2) = 0.1353
I assume you're just solving for x. Factorize the left side as
3 sin²(x) - 3 sin⁴(x) = 3 sin²(x) (1 - sin²(x)) = 0
Recall that
sin²(x) + cos²(x) = 1
so that the equation further reduces to
3 sin²(x) cos²(x) = 0
Also recall the double angle identity,
sin(2x) = 2 sin(x) cos(x)
which lets us rewrite the equation as
3/2² (2 sin(x) cos(x))² = 3/4 sin²(2x) = 0
Solve for x :
3/4 sin²(2x) = 0
sin²(2x) = 0
sin(2x) = 0
2x = arcsin(0) + 2nπ or 2x = π - arcsin(0) + 2nπ
(where n is any integer)
2x = 2nπ or 2x = (2n + 1) π
x = nπ or x = (2n + 1)/2 π
Notice that this means the solution set is
{…, -2π, -3π/2, -π, -π/2, 0, π/2, π, 3π/2, 3π, …}
so we can condense the solution further to
x = nπ/2
with any integer n.