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2 years ago

I need help!

Mathematics

1 answer:

kvasek [131]2 years ago

7 0

Answer:

812.5

Step-by-step explanation:

900÷72=12.5

65×12.5=812.5

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Suppose the mean SAT verbal score is 525 with a standard deviation of 100, while the mean SAT math score is 575 with a standard

Ipatiy [6.2K]

Answer:

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

Step-by-step explanation:

Normal variables

Normal variables have mean $\mu$ and standard deviation $\sigma$

When we add normal variables, the combined mean is the sum of both means, and the standard deviation is the square root of the sum of both variances. The distribution is still normal.

In this question:

Verbal: $\mu_{V} = 525, \sigma_{V} = 100$ .

Math: $\mu_{M} = 575, \sigma_{M} = 100$

Combined:

$\mu = \mu_{V} + \mu_{M} = 525 + 575 = 1100$

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The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

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2 years ago

Joshua is 1.45 meters tall. At 2 p.m., he measures the length of a tree's shadow to be 31.65 meters. He stands 26.2 meters away

Lena [83]

Answer:

The height of the tree=8.42 m

Step-by-step explanation:

We are given that

Height of Joshua, h=1.45 m

Length of tree's shadow, L=31.65 m

Distance between tree and Joshua=26.2 m

We have to find the height of the tree.

BC=26.2 m

BD=31.65m

CD=BD-BC

CD=31.65-26.2=5.45 m

EC=1.45 m

All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.

$\triangle ABD\sim \triangle ECD$

$\frac{AB}{EC}=\frac{BD}{CD}$

Substitute the values

$\frac{AB}{1.45}=\frac{31.65}{5.45}$

$AB=\frac{31.65\times 1.45}{5.45}$

$AB=8.42m$

Hence, the height of the tree=8.42 m

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2 years ago