Answer:
I figure that the answer is 1.6 because to find a, you do 24 divided by 15.
As a decimal, that is 17.625, which rounds up to 18.
Answer:
m = 15.
Step-by-step explanation:
∛(3375) = 15.
You can use a calculator to do this. Some calculators have a direct key giving you a cube root or you can use the power key + 1/3 .
Note: ∛(3375) = 3375^(1/3).
Answer:
Length of the final sides: 6 cm and 16 cm
Step-by-step explanation:
The lengths of the sides of the original box are
![L=20 cm\\W=10 cm](https://tex.z-dn.net/?f=L%3D20%20cm%5C%5CW%3D10%20cm)
Later, a piece of tin is cut out from each corner; the piece cut out has the shape of the square: we can call the length of its generic side x. Therefore, the dimensions of the box will now be:
![L'=L-2x\\W'=W-2x](https://tex.z-dn.net/?f=L%27%3DL-2x%5C%5CW%27%3DW-2x)
We also know that the area is
![A=96 cm^2](https://tex.z-dn.net/?f=A%3D96%20cm%5E2)
And the area can be written as product of length and width, therefore:
![A=L'W'](https://tex.z-dn.net/?f=A%3DL%27W%27)
So we find:
![A=(L-2x)(W-2x)\\96=(20-2x)(10-2x)](https://tex.z-dn.net/?f=A%3D%28L-2x%29%28W-2x%29%5C%5C96%3D%2820-2x%29%2810-2x%29)
Solving for x,
![96=200-20x-40x+4x^2\\4x^2-60x+104=0\\\\x^2-15x-26=0](https://tex.z-dn.net/?f=96%3D200-20x-40x%2B4x%5E2%5C%5C4x%5E2-60x%2B104%3D0%5C%5C%5C%5Cx%5E2-15x-26%3D0)
Which has two solutions:
x = 13 cm (this is larger than the initial length of the width, therefore we discard it)
x = 2 cm
So, the length of the new sides are
![L=20-2x=20-2(2)=16 cm\\W=10-2x=10-2(2)=6 cm](https://tex.z-dn.net/?f=L%3D20-2x%3D20-2%282%29%3D16%20cm%5C%5CW%3D10-2x%3D10-2%282%29%3D6%20cm)
Answer:
3
Step-by-step explanation:
by using formula
t²-t¹
which means
-3-(-6)
=3