No, you divide 21.88 by 4.
Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
So you convert the fraction into a decimal then multiply it by 100 so the percentage would be 180%
Answer:
23.44%
Step-by-step explanation:
The probability of getting a 4 on the first 2 throws and different numbers on the last 5 throws = 1/6 * 1/6 * (5/6)^5
= 0.01116
There are 7C2 ways of the 2 4's being in different positions
= 7*6 / 2 = 21 ways.
So the required probability = 0.01116 * 21
= 0.2344 or 23.44%.
Answer:
9. x>-4 or x≥1
10. a<2 or a≥-5
11. v≤7 or v≥-4
12. k≥5 or k<8
13. n>6.8 and n≤9
Step-by-step explanation:
9. -2x-7>1
-2x>8
x>-4
x-2≥-1
x≥1
10.a/-2 <-1
a<2
-4a+3≥23
-4a≥20
a≥-5
11. 6v+38≤-4
6v≤-42
v≤7
2(v+3)≥-2
2v+6≥-2
2v≥-8
v≥-4
12. 4(1-k)≥-16
4-4k≥-16
-4k≥-20
k≥5
7-6k<-41
-6k<-48
k<8
13. 10n-9>-59
10n>-68
n>6.8
n-6≤3
n≤9
