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sweet-ann [11.9K]
2 years ago
8

What changes when the parent function

"f(x)=x^2" align="absmiddle" class="latex-formula"> is stretched by a positive factor?
Mathematics
1 answer:
Karolina [17]2 years ago
6 0

9514 1404 393

Answer:

  • vertical stretch: the function value (f) is multiplied by the stretch factor
  • horizontal stretch: the variable (x) is divided by the stretch factor

Step-by-step explanation:

A stretch can be vertical, horizontal, or both.

Multiplying the function value by a factor greater than 1 will stretch the graph vertically.

Dividing the variable value by a factor greater than 1 will stretch the graph horizontally.

__

The graph is stretched by the factor according to how it is applied.

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A researcher wants to determine whether the number of minutes adults spend online per day is related to gender. A random sample
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Answer:

The expected frequency for the cell E2,2 is = 33

Step-by-step explanation:

The given data is

Gender               | 0-30| 30-60| 60-90| 90+       Totals

Male                    | 23    |    35   |   76    |  46        180

<u> Female               |   31   |    42   |   46    |  16         135    </u>

<u>Totals                    54         77        122    62          315  </u>

<u />

The expected frequency for the cell E2,2 is :

Expected for the (30-60 box for females)   =  Total of (30-6)/ (total )* females

                                                                      = ( 77/315)135= 33

Here p= 77/315 and n= 135

therefor X= pn = 33

χ²=  (33-42)²/33= 2.455  ( for the single value of E2,2=33)

Expected for the (30-60 box for males)   =  Total of (30-6)/ (total )* males

                                                                      = ( 77/315)180= 44

χ²=  (44-42)²/44= 0.09

The critical region is  χ² (0.05) 3 ≥  χ²= 11.34

Let the null and alternate hypothesis be

H0:the number of minutes spent online per day is not related to gender

against

Ha: the number of minutes spent online per day is related to gender

The single value of χ² for E2,2 = 2.45 is less than the critical value of 11.34.  

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