Answer:
Step-by-step explanation:
We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.
We know that equation of an object's height t seconds after the launch is in form 
, where
g = Force of gravity,
= Initial velocity,
= Initial height.
For our given scenario 
, 
and 
. Upon substituting these values in object's height function, we will get:
Therefore, the function for the height of the arrow would be .
(a) Complementary angles
(b) Vertical angles
(c) Supplementary angles
<u>Explanation:</u>
Complementary angles are those two angles whose sum is 90 degrees.
Supplementary angles are those two angles whose sum is 180 degrees.
Vertical angles are the angles opposite each other when two lines cross.
(a)
Angles 1 and 5 are complementary angles
(b)
Angles 3 and 5 are vertical angles
(c)
Angles 3 and 4 are supplementary angles
Answer: 5, -4, 2.6, and 100
Step-by-step explanation:
Answer:
33x-25
Step-by-step explanation:
2(3x-5)-3(6-4x)+(15x+3)
6x-10-18+12x+15x+3
21x+12x-10-18+3
=33x-25
