All categories

3 years ago

10Hello, can you help me with this? How much is 5 raised to 5?

Mathematics

1 answer:

vesna_86 [32]3 years ago

6 0

Answer:

A 5 by 5 Power in Trust is a clause that lets the beneficiary make withdrawals from the trust on a yearly basis. The beneficiary can cash out $5,000 or 5% of the trust's so-called fair market ...

Step-by-step explanation:

5^5

=5*5*5*5*5

=5^5

=3125

You might be interested in

Is an imaginary "line" from the Earth to the Moon a line, a ray, or a segment? and WHY?

sesenic [268]

Answer:

Segment

Step-by-step explanation:

It is a segment because it has two endpoints (the Earth and Moon). If it was a ray, it would go on forever in one direction. It doesn't, so the imaginary line is a segment.

The first image is a segment, the second is a ray.

Hope this helps. :)

7 0

3 years ago

Drake wants to save $750 so that he can take a class on computer analysis for cars. The class is being held on various dates ove

Galina-37 [17]

Answer: c

Step-by-step explanation:

3 0

3 years ago

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .