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3 years ago

Help pls. Given l || m || n, find the value of x.

Mathematics

2 answers:

ololo11 [35]3 years ago

4 0

Answer:

Step-by-step explanation:

By transversal parallel lines theorem, x=41

barxatty [35]3 years ago

4 0

answer:

x = 41

- use the rules to solve it

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Step 1 he had to multiply the $22.75 times 3 weeks it should have been
($22.75 x 3) + $32.75 - $14.25
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3 years ago

Please help quickly!! thanks!! :))

Svetlanka [38]

ANSWER:D

Explained:
When in form y=mx+c , the c is the y intercept

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So Y=-x+8 becomes...
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3 years ago

Alfonso uses a payroll deduction to deposit $120 into his

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Step-by-step explanation:

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2 years ago

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Factor each: x^8-13x^4+36=0

Hoochie [10]

Answer:

Step-by-step explanation:

a = x^4

a^2 - 13a +36 = 0

(a-4)*(a-9)=0

a = 4, a = 9

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3 years ago

For each equation, determine whether it has no solutions, exactly one solution, or is true for all values of x (and has infinite

nignag [31]

Answer:

Equation 1 has exactly one solution.
Equation 2 has infinitely many solutions.
Equation 3 has no solution.

Step-by-step explanation:

We are given three equations to solve. First, let's solve the equations for x.

Equation 1

$\displaystyle{6x+8=7x+13}\\\\7x + 13 = 6x + 8\\\\x + 13 = 8\\\\\bold{x = -5}$

Therefore, we determined that for the first equation, x = -5. We can check our solution by substituting it back into the original equation.

$\displaystyle{6(-5)+8=7(-5)+13}\\\\-30 + 8 = -35 + 13\\\\-22 = -22 \ \checkmark$

Since we got a true statement, there are no other values of x for which we get a true statement. Let's test this with the opposite value: positive 5.

$6(5)+8=7(5)+13\\\\30 + 8 = 35 + 13\\\\38 = 48 \ \text{X}$

Therefore, for Equation 1, there is exactly one solution.

Equation 2

$6 x + 8 = 2 ( 3 x + 4 )\\\\6x + 8 = 6x + 8\\\\0 + 8 = 8\\\\8 = 8 \ \checkmark$

We get a true statement by solving for x (which ends up canceling out of the equation entirely). Therefore, we can check any value in place of x to see if we get a true statement. For this instance, I will use -3.

$6(-3) + 8 = 2 ( 3(-3) + 4 )\\\\-18 + 8 = 2(-9+4)\\\\-18 + 8 = 2(-5)\\\\-18 + 8 = -10\\\\-18 = -18 \ \checkmark$

We still get a true statement, so Equation 2 has infinitely many solutions.

Equation 3

$6 x + 8 = 6 x + 13\\\\0 + 8 = 13\\\\8 \neq 13$

We get a false statement. Therefore, Equation 3 has no solution.

3 0

3 years ago

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