Question

​claim: the mean pulse rate​ (in beats per​ minute) of adult males is equal to 6969 bpm. for a random sample of 125125 adult​ males, the mean pulse rate is 69.269.2 bpm and the standard deviation is 10.910.9 bpm. find the value of the test statistic. the value of the test statistic is nothing. ​(round to two decimal places as​ needed.)

Answer 1

Answer:

t=0.21

Step-by-step explanation:

Given  $\bar x=69.2, s=10.9, n=125$and a population mean $\mu=69$.

#We state our hypothesis as:

$H_o:\mu=69\\\\H_a:\mu\neq 69$

The evidence available should validate either the null or alternative hypothesis.

#We calculate the test statistic as:

$t=\frac{\bar x-\mu_}{s/\sqrt{n}}\\\\\\=\frac{69.2-69}{10.9/\sqrt{125}}\\\\\\=0.2051$

$\approx0.21$

Hence, the test statistic is t=0.21