Is an integer that is the square root of an integer ex 4 which can be written 2times 2
Answer:
1) Since AP/AB=PQ/BC, 6x/(3x+5)=x/1. Cross multiply the denominator and you will get 6x=(3x+5)*x. Simplifying it more and you are left with 3x^2-x=0
2) 3x^2-x=0. x(3x-1)=0. x=0 or x=1/3 but x=0 can't be a solution since it would make the figure absurd. x=1/3 cm
3) According to the figure PB=AB-AP=3x+5-6x=-3x+5.
PB=-3*(1/3)+5=4 cm
-30-6r=36
We move all terms to the left:
-30-6r-(36)=0
We add all the numbers together, and all the variables
-6r-66=0
We move all terms containing r to the left, all other terms to the right
-6r=66
r=66/-6
r=-11
54 because if x+y=82 and x-y=26 add 26 and 82 is 108 the divide it by 2 your answer is 54
<span>For problem 8:
sin A/a sinB/b = sinC/c
so sin50/15 = sinB/12
0.766/15 =sinB/12
0.051066 = sin B/12
sin B = 0.6128
B = 37.79 degrees
sum of angles must equal 180 deg therefore C = 180-50-37.79 = 92.21 degrees and .766/15 = sin92.21/c
.051066= 0.99925/c
c = .99925/0.051066 = 19.567
Problems 9 and 10 can also be done with the same method as problem 8.
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