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Setler [38]
3 years ago
13

I shall return again; I shall return

Chemistry
1 answer:
victus00 [196]3 years ago
5 0

Answer:

that's a very pretty poem but what's a question?

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Match each lab incident to the item of PPE that will protect you from it. Each item of PPE will only be used once.
andre [41]

Answer:

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3 years ago
How many protons are in an atom of strontium?
Stells [14]

Answer:

38

Explanation:

Symbol: Sr

Atomic mass: 87.62 u

Electrons per shell: 2,8,18,8,2

Atomic number: 38

Electron configuration: [Kr] 5s2

Van der Waals radius: 255 pm

Valence electrons: two

7 0
4 years ago
As a chemical reaction occurs, the thermometer in the container records a drop in temperature. What is true of the reaction?
nadya68 [22]
<span>When a chemical reaction occurs and the thermometer in the container records a drop in temperature t</span>he reaction is exothermic because heat was released by the reaction.

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4 0
3 years ago
Read 2 more answers
What type of bond does sodium and bromine form?
vitfil [10]
Sodium is a metal and bromine is a nonmetal so they form an ionic compound
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7 0
3 years ago
The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s
raketka [301]

Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

Explanation :

The dissociation of acid reaction is:

                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

K_a=6.3\times 10^{-5}

The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

Thus, the equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

4 0
3 years ago
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