We need to know some log properties
1. when the base is not stated, assume that it is base 10 or log₁₀
2.

-log(10^-1)=

answer is D. -1
48.9 / 4 = 12.225
distance = 100m
time = 12.225 sec
v = d/t
The answer is 8.1799
Answer:
a. 54.05 Mpbs.
b. 2.745... standard deviations.
c. The z-score is 2.745....
d. The carrier's highest data speed is significantly high.
Step-by-step explanation:
a. The difference between the highest measured data speed and the mean is 72.6 - 18.55 = 54.05 Mbps.
b. The amount of standard deviations of 54.05 Mbps is equal to this value divided by the standard deviations, so we yield
standard deviations.
c. The z-score is equal to the difference between the mean and a data point in standard deviations, so the z-score is 2.745....
d. 2.745... is not between -2 and 2, so the carrier's highest data speed is not insignificant - so it's significantly high.
The answer is -8 I know this as well as