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Zepler [3.9K]
3 years ago
14

Is x-5 a factor of p(x)=x^3-6x^2-x+30

Mathematics
1 answer:
Arada [10]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

Dividing :  x3-6x2-x+30

                             ("Dividend")

By         :    x-5    ("Divisor")

dividend     x3  -  6x2  -  x  +  30

- divisor  * x2     x3  -  5x2        

remainder      -  x2  -  x  +  30

- divisor  * -x1      -  x2  +  5x    

remainder          -  6x  +  30

- divisor  * -6x0          -  6x  +  30

remainder                0

Quotient :  x2-x-6  Remainder:  0

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