No. The area doesn't tell you the dimensions, and you need
the dimensions if you want the perimeter.
If you know the area, you only know the <em><u>product</u></em> of the length and width,
but you don't know what either of them is.
In fact, you can draw an infinite number of <em><u>different</u></em> rectangles
that all have the <em>same</em> area but <em><u>different</u></em> perimeters.
Here. Look at this.
I tell you that a rectangle's area is 256. What is its perimeter ?
-- If the rectangle is 16 by 16, then its perimeter is 64 .
-- If the rectangle is 8 by 32, then its perimeter is 80 .
-- If the rectangle is 4 by 64, then its perimeter is 136 .
-- If the rectangle is 2 by 128, then its perimeter is 260 .
-- If the rectangle is 1 by 256, then its perimeter is 514 .
-- If the rectangle is 0.01 by 25,600 then its perimeter is 51,200.02
Answer:
im not exactly sure but i think it would be y=1x-2
Answer:
Step-by-step explanation:
1. y = 4x - 3
2. y = -x + 4
3. y = 1/3x +1
4. y = ----
5. y = 1/7x + 2
6. y = -4x + 2.75
7. y = 3x + 5
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You can exploit the difference-of-squares identity,
<em>a</em>² - <em>b</em>² = (<em>a</em> - <em>b</em>) (<em>a</em> + <em>b</em>)
Then
101.5² - 100.5² = (101.5 - 100.5) * (101.5 + 100.5)
101.5² - 100.5² = 1 * 202
101.5² - 100.5² = 202
