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Iteru [2.4K]
3 years ago
5

Write a sentence with a perso in it for this. 2n + 4 = 24

Mathematics
1 answer:
RideAnS [48]3 years ago
5 0

Josh has (n) amount of candy. He found 4 more pieces of candy on his kitchen counter. Josh counted his total pieces of candy and figured out he has 24 total pieces.


Hope I helped have a wonderful day...

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1, create the equation and then solve.
ser-zykov [4K]

Answer:

52-x=14   38

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52 players were playing until the server crashed, only fourteen remained after 38 disconnected.

6 0
2 years ago
How can I solve this problem
Rzqust [24]
What a terrible question. I'm sorry you have this teacher. I think the answer they are looking for is 42 even though there's that +/- should be in a parenthesis and then you are rounding 6.5² to 42. Hope this helps
3 0
3 years ago
Abe needs 13.5 feet to make a bedspread. How many yards does he need?
riadik2000 [5.3K]
4.5 is the answer because
first I took out the decimal which the new number is now 13
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6 0
3 years ago
Is 17 rational or irrational
Fantom [35]

Answer:

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6 0
2 years ago
"Lashonda swam 4 kilometers against the current in the same amount of time it took her to swim 16 kilometers with the current. T
Naddika [18.5K]

Answer:

5 km/h

Step-by-step explanation:

In this problem, Lashonda swam 4 km against the current. So the distance covered in this case is

d_1=4 km

Calling v the velocity of Lahonda without the current, and c the velocity of the current, in this situation Lahonda's velocity is

v-c

So we can write:

t_1=\frac{d_1}{v-c}

where t_1 is the time taken to cover the distance.

When Lashonda swims with the current, her velocity is

v+c

So we can write

t_2=\frac{d_2}{v+c}

where

d_2=16 km is the distance covered in this case, and t_2 the time taken.

The velocity of the current is

c=3 km/h

Since Lashonad takes the same time to cover the two distances,

t_1=t_2

So we can write

\frac{d_1}{v-c}=\frac{d_2}{v+c}

And solving for v, we find Lashonda's velocity without the current:

d_1(v+c)=d_2(v-c)\\d_1 v+d_1c = d_2v-d_2c\\v(d_2-d_1)=c(d_1+d_2)\\v=\frac{d_2+d_2}{d_2-d_1}c=\frac{16+4}{16-4}(3)=5 km/h

7 0
3 years ago
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