Yes it’s a rational number
Answer:
Probability that in a random sample of six cities, the sample mean would be more than 40 is 0.3372.
Step-by-step explanation:
We are given that the percent of births to mothers with less than a college education in all of the most populated cities in the U.S. has an average of 39.3 with a standard deviation of 4.1.
Assuming the data follows distribution. Also, a random sample of six cities is selected.
<em>Firstly, Let </em><em> = sample mean of six cities</em>
The z score probability distribution for sample mean is given by;
Z = ~ N(0,1)
where, = average percent of births = 39.3
= standard deviation = 4.1
n = sample of cities = 6
Probability that in a random sample of six cities, the sample mean would be more than 40 is given by = P( > 40)
P( > 40) = P( > ) = P(Z > 0.42) = 1 - P(Z 0.42)
= 1 - 0.66276 = 0.3372
Therefore, probability that the sample mean would be more than 40 is 0.3372.
No it is not two ones is two ones and twenty tenths is 200 so 200 would be 2 100 grids and two ones would be two squares
Answer:
About <u><em>5 minutes </em></u>each lab.
Step-by-step explanation:
Hope this helped! :)