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Alex17521 [72]
3 years ago
12

Help plz I really need to pass

Mathematics
1 answer:
Tresset [83]3 years ago
3 0

Answer:

2.56

Step-by-step explanation:

The equation they dive u: d = 16t^2, so in the question they said what's the distance, d, if t = 0.4

So you just have to replace t with 0.4:

d = 16t^2

d = 16(0.4)^2

d = 16(0.16)

d = 2.56

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Supriya is decorating her bedroom. She plans to hang strings of twinkle lights all the way around her walls. She measures the wa
DaniilM [7]

Perimeter

Perimeter is the distance all round a particular shape. Since we are not given the shape of her bedroom, we may not have a particular formula that was uses to find the perimeter. Despite all that, the only way that she could arrive to conclusion that 36 meters of light are needed, then Supriya it is by finding the perimeter.

Step-by-step explanation:

3 0
3 years ago
A genetic experiment involving peas yielded one sample of offspring consisting of 420 green peas and 174 yellow peas. Use a 0.01
slavikrds [6]

Answer:

a) z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

b) For this case we need to find a critical value that accumulates \alpha/2 of the area on each tail, we know that \alpha=0.01, so then \alpha/2 =0.005, using the normal standard table or excel we see that:

z_{crit}= \pm 2.58

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

Step-by-step explanation:

Data given and notation

n=420+174=594 represent the random sample taken

X=174 represent the number of yellow peas

\hat p=\frac{174}{594}=0.293 estimated proportion of yellow peas

p_o=0.23 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of yellow peas is 0.23:  

Null hypothesis:p=0.23  

Alternative hypothesis:p \neq 0.23  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>3.649)=0.00026  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

b) Critical value

For this case we need to find a critical value that accumulates \alpha/2 of the area on each tail, we know that \alpha=0.01, so then \alpha/2 =0.005, using the normal standard table or excel we see that:

z_{crit}= \pm 2.58

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

5 0
3 years ago
{0, 1, 2, 3, 4, . . . , 148, 149, 150} How many members of the above set are multiples of 3 but not multiples of 5? *
umka2103 [35]

Answer:

The answer is 40.  

Step-by-step explanation:

First you can simply just list the multiples of 3 from 1-150, then cancel out all the multiples of 5 so,

3, 6, 9, 12, 18, 21, 24, 27, 33, 36, 39, 42, 48, 51, 54, 57, 63, 66, 69, 72, 78, 81, 84, 87, 93, 96, 99, 102, 108, 111, 114, 117, 123, 126, 129, 132, 138, 141, 144, 147.

15,30,45, 60,75,90, 105, 120,135 and 150 are multiples of 5 and so they are not included.

3 0
3 years ago
Help needed ASAP will give BRAINLIEST and 5 Stars rate
garri49 [273]
(-3, 3) because it is the intersection point.
7 0
3 years ago
Jodi built a rectangular sandbox for her daughter. The sandboxmeasures6 feet by 5feet by 1.2 feet. Jodi purchases 20cubic feet o
Mamont248 [21]

For this case, the first thing to do is to model the rectangular sandbox as a rectangular prism.

The volume of the prism is given by:

V = w * l * h

Where,

  • <em>w: width </em>
  • <em>l: length </em>
  • <em>h: height </em>

Therefore, replacing values we have:

V = 6 * 5 * 1.2\\V = 36 ft ^ 3

We observed that:

36 ft ^ 3> 20 ft ^ 3

Therefore, the sandbox is not completely filled.

Answer:

the sandbox will hold 36 ft ^ 3 of sand

Jodi purchase is not enough sand to fill the sandbox to the top.

36 ft ^ 3> 20 ft ^ 3

8 0
3 years ago
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