16 ears of corn are being picked for every 18 peppers if 9 peppers have been picked how many ears of corn have been picked

It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To test this claim, 100 randomly sele

kow [346]

Answer:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

$p_v =P(t_{99}>8.974)=9.43x10^{-15}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.

Step-by-step explanation:

1) Data given and notation

$\bar X=23500$ represent the sample mean

$s=3900$ represent the sample standard deviation

$n=100$ sample size

$\mu_o =2000$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20000, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2000$

Alternative hypothesis: $\mu > 2000$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=100-1=99$

Since is a one-side upper test the p value would be:

$p_v =P(t_{99}>8.974)=9.43x10^{-15}$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.

8 0

3 years ago

Unless otherwise posted, what is the speed limit in a residential area?

raketka [301]

Residential speed limit is 40 mph unless otherwise posted. Residential speed limit is 30 mph unless otherwise posted.

hope this helped

mark brainliest :)

6 0

3 years ago

-7 times -8? -40 divided by 10?

alekssr [168]

-7 times -8 is 56 and -40 divided by 10 is -4

4 0

3 years ago

Cassie wants to buy carpet to cover her whole living room, except for the tiled floor. The tiled floor is 4

SIZIF [17.4K]

Answer:

1456

Step-by-step explanation:

56x2x13

56x26

1456

5 0

2 years ago

A shelter in the city house birds and dogs . There are 25% more dogs then birds. If there are 50 birds how many dogs are there?

AfilCa [17]

Answer:

They have 83 dogs and 50 birds.

There are 133 animals in total in the shelter.

Step-by-step explanation:

So let's call the dogs D and the birds B.

D = 25% + B

What ever the amount of animals, the total for D must always be 25% more than B.

To get 100% of the animals, B must equal 37.5% and D must equal 62.5%.

The way I worked this out was:

100% - 25%= 75%

75% divided by 2= 37.5%

37.5% + 25%= 62.5%

And just to check

37.5% + 62.5% = 100%

So to work out 100%:

37.5% = 50

divide both by 37.5 to get 1%

1% = 1.333333

time both by 62.5 to get 62.5%

62.5% = 83.333313

We'll round that answer because I'm pretty sure they don't have a .333313th of a dog.

So D = 62.5% = 83

They have 83 dogs and 50 birds.

Phew! That was the hard part. Now onto something wayyy easier.

To get the total number of animals in the shelter we just do 83 + 50, which is 133.

There are 133 animals in total in the shelter.

Hope this helps you :)

7 0

2 years ago