Mr. and Mrs. Bailey need to invest $2906.50 so as to send their son to college.
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Compound interest</h3>
Compound interest is given by:

where A is the amount after t years, P is initial amount, r is the rate and n is the times compounded per period
Given that n = 1, r = 9% = 0.09, A = $7500 t = 11. Hence:

Mr. and Mrs. Bailey need to invest $2906.50 so as to send their son to college.
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Answer: 21/5
Step-by-step explanation:
We reject our null hypothesis, H₀, at a level of significance of =0.01 since the P-value is less than that threshold. There is compelling statistical data to indicate that since 1991, the proportion of drivers who love driving has decreased.
Given,
The Pew Research Center recently polled n=1048 U.S. drivers and found that 69% enjoyed driving their automobiles.
In 1991, a Gallup poll reported this percentage to be 79%. using the data from this poll, test the claim that the percentage of drivers who enjoy driving their cars has declined since 1991.
To report the large-sample z statistic and its p-value,
Null hypothesis,
H₀ : p = 0.79
Alternative hypothesis,
Ha : p < 0.79
Level of significance, α = 0.01
Under H₀
Test statistic,

Z₀ = -7.948
The alternative hypothesis(Ha) is left-tailed, so the P-value of the test is given by
P-value = P(z <-7.945)
= 0.000 (from z-table)
Since the P-value is smaller than given level of significance, α=0.01 we reject our null hypothesis, H₀, at α=0.0.1 level Strong statistical evidence to conclude that the percentage of drivers who enjoy driving their cars has declined since 1991.
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Answer:
Rosaria purchased 50 bracelets and 70 necklaces
Step-by-step explanation:
Let the number of bracelets be b and the number of necklaces be n
b + n = 120 •••••(i)
Secondly;
10b + 11n = 1270 ••••(ii)
Total cost of b bracelets at 10 per 1 is 10b
Total cost of n bracelets at 11 per 1 is 11n
Adding both gives 1270
From i, b = 120-n
Substitute this into ii
10(120-n) + 11n = 1270
1200 - 10n + 11n = 1270
n = 1270-1200
n = 70
b = 120-n
b = 120-70
b = 50
Answer:
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