Answer:
3x +15y +7z = 46
Step-by-step explanation:
The cross product of v = <2, 1, -3> and PQ = <-5, 1, 0> is <3, 15, 7>, the normal vector of the plane of interest. That plane contains P and Q, so the constant in the plane's equation will be ...
<3, 15, 7> · <3, 2, 1> = 46
The desired equation is ...
3x +15y +7z = 46
Answer:
The answer would be 11.3
Step-by-step explanation:
All you have to do is figure out how far one is from the other so from 7.8 I went back to 0 of course the Y coordinate stays the same. So then you get the -3.5 make it a positive so just 3.5 and then add to 7.8 to get 11.3
Hope this helped.
A brainliest is always appreciated.
Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.
Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.
Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7
Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18
Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.
Answer: 37,39,41,43
Answer:
Step-by-step explanation:
<u>Given expression:</u>
<u>Distribute this to get:</u>
- a(b + c) = ab + ac
- 5(2 + 7) = 5(2) + 5(7)
Correct choice is D
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