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lutik1710 [3]
3 years ago
9

Find the 14th term of the geometric sequence 2,6,18, ...

Mathematics
2 answers:
Bumek [7]3 years ago
8 0

Answer:

Step-by-step explanation:

The answer to this question link is here

https://socratic.org/answers/623991

riadik2000 [5.3K]3 years ago
8 0

The geometric sequence is starting with 2 and multiplying by 3 every time. We can get the rule of this sequence by...

  • If 2 is a_{1}, 6 is a_{2}, 18 is a_{3}, etc...
  • then, a_{n}=2(3)^(n - 1)

For the 14th term, plus in 14 for n, and it will look like this:

= 2(3)^(14 -1)

= 2(3)^(13)

= 3188646

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wolverine [178]

Answer:

x = -1 ± √6 / 5

Step-by-step explanation:

Solve 5x^{2} + 2x = 1

move 1 to the left side of the equation by subtracting it from both sides.

5x^{2} + 2x - 1 = 0

Use the quadratic formula to find the solutions.

-b± \sqrt{b^2 - 4 (ac)}/ 2a

Substitute the values a = 5 , b = 2, and c = -1 into the quadratic formula and solve for x

-2±\sqrt{2^2 - 4(5 - 1)}/ 2 ⋅ 5

Simplify.

x = -2 ± 2 \sqrt{6}/ 10

x = -1 ± \sqrt{6}/ 5

Exact Form:

x = -1 ± \sqrt{6}/ 5

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Answer:

Step-by-step explanation:

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