Answer:
The volume of the geometric solid produced is 391 cubic cm ⇒ A
Step-by-step explanation:
<em>When a </em><em>right triangle is rotated about its vertical leg 360°</em><em>, then it formed </em><em>a cone</em><em> its radius is the horizontal leg of the triangle and its height is the vertical lege of the triangle.</em>
The rule of the volume of the cone is V = 
π r² h, where
- r is the radius of its base
- h is the length of its height
∵ Triangle XYZ is rotated 360° about the vertical side YZ
∴ It formed a cone with a radius = XZ and a height = YZ
∵ 
∵ YX = 6√3
∴ 
∵ tan(60) = √3
∴ 
= √3
→ By using cross multiplication
∴ 6√3 = XZ(√3)
→ Divide both sides by √3
∴ 6 = XZ
∵ XZ = r and YZ = h
∴ r = 6 and h = 6√3
→ By using the rule of the cone above
∵ V = (π) (6)² (6√3)
∴ V ≅ 391 cm³
∴ The volume of the geometric solid produced is 391 cubic cm
Answer:
<h2>2 and three-fourths </h2>
Step-by-step explanation:
Given the expression 
, the equivalent expression can be gotten as shown;
2 and three-fourth therefore gives the required expression
I believe the answer is Diane brought 4 pounds of coffee.
The probabillity can be found by using binomial probability formular considering that the event is discrete in nature and there are two possiple outcomes.
Answer:
Step-by-step explanation:
The mean SAT score is 
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it 
) is
Next they draw a random sample of n=70 students, and they got a mean score (denoted by 
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form
and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.
<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
