<span>The line of symmetry of the triangle bisects the right angle and the diagonal of the square.
The line is 1/2 the length of the square's diagonal :
(1/2)(10√2) = 5√2.
</span>Let CG be a distance x from the vertex of the right angle in the triangle.
Remaining distance = 5√2 - x.
<span>
(1)(x) = (2)(5√2 - x)</span>
x = 10√2 - 2x
<span>3x = 10√2 </span>
<span>x = (10/3)√2.
</span>
Using Pythagorean theorem,
x^2 + y^2 = c^2
<span>c = (10/3)√2,
and x = y,
so 2x^2 = 200/9
x = √(100/9) = 10/3 = y.
</span>
<span>x = y = 3.333</span>
Answer:
14
Step-by-step explanation:
PEMDA ( ( ), ^, x, ÷, +, -)
write equation
(2x4) + (12x2) ÷ 4 =?
solve
(2x4) = 8
rewrite
8 + (12x2) ÷ 4
solve
(12x2) =24
rewrite
8 + 24 ÷ 4
solve
24 ÷ 4 = 6
rewrite
8 + 6
Solve
8+6=14
Answer = 14
Hope this helped!
~Lunar Rose. Moon
Answer:
133
Step-by-step explanation:
The two angles add to a straight line
PQR + RQS = PQS
3x-5 + x+1 = 180
Combine like terms
4x -4 =180
Add 4 to each side
4x -4+4 = 180+4
4x =184
Divide each side by 4
4x/4 =184/4
x =46
We want to find PQR
PQR = 3x-5
= 3*46 - 5
= 138 -5
= 133
The answer would be 14x+5 I’m pretty sure
