Answer:
Step-by-step explanation:
Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.
Suppose that one employee is selected at random from a list of the employees
A) Probability that the selected employee has been with the firm less than 5 years = 
B) Probability that the selected employee has been with the firm between 5 and 10 years
= 
C) Probability that the selected employee has been with the firm more than 10 years
= 
a) P(A) = 0.2
P(C) = 0.5
P(A or B) = 0.2+0.3 = 0.5
P(A and C) = 0 (since A and C are disjoint)
The answer is A. Slope is rise/run. According to the graph, you can trace out and see that it rises 1 and goes to the right 4 times. This means that it has a positive slope of 1/4. And the line crosses the y intercept at y = 3
So answer choice A is correct.
6a-(n-1)(3a) is the nth term
Expanding we get 6a-3an+3a=9a-3an=3a(3-n)
SOLUTION: nth term is 3a(3-n)